Answer:
The concentration of the newly prepared solution is 8 * 10^-5 M
Explanation:
The most common way to solve this problem is to use the following formula
c1*V1 = c2*V2
with c1 = 1 * 10^-3 M
with V1 = 20 mL = 0.02 L
with c2 = TO BE DETERMINED
with V2 = 250 mL = O.250 L
10^-3 * 0.02 L = c2 * 0.250L
0.00002 = c2 * 0.250L
c2 = 0.00002 / 0.250 L
c2 = 0.00008 M = 8 * 10^-5 M
The concentration of the newly prepared solution is 8 * 10^-5 M
Answer:
Explanation:1) ΔrH = 2mol·ΔfH(NO) - (ΔfH(O₂) + ΔfH(N₂)).
ΔrH = 2 mol · 90.3 kJ/mol - (0 kJ/mol + 0 kJ/mol).
ΔrH = 180.6 kJ.
2) ΔS = 2mol·ΔS(NO) - (ΔS(O₂) + ΔS(N₂)).
ΔS = 2mol · 210.65 J/mol·K - (1mol · 205 J/mol·K + 1 mol · 191.5 J/K·mol).
ΔS = 24.8 J/K.
3) ΔG = ΔH - TΔS.
55°C: ΔG = 180.6 kJ - 328.15 K · 24.8 J/K = 172.46 kJ.
2570°C: ΔG = 180.6 kJ - 2843.15 K · 24.8 J/K = 110.09 kJ.
3610°C: ΔG = 180.6 kJ - 3883.15 K · 24.8 J/K = 84.29 kJ.
Answer:
Lake
Explanation:
Yeah...not much else to say honestly
Answer:
Water is the solvent
Both the ethanol and the hydrogen peroxide are the solute
Explanation:
Both the hydrogen peroxide and ethanol are sisobable in water.
There are 0.05 moles of ethanol.
1 litreof water contains 55.55 moles of water.
0.2 g of hydrogen peroxide contains 0.2/34 = 0.0059 moles of hydrogen peroxide (the 34 is the molar mass of hydrogen peroxide).
Since there are more moles of water, water becomes the solvent and the other two liquids dissolve in it.
<span>A full filled atom is more
stable than the half filled atom. This is because it has an equal number of
protons and electrons. The protons cancel out the electrons and thus
giving it a net charge of zero. It cannot be further ionized.</span>
