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Elza [17]
2 years ago
12

What is differentiation​

Engineering
1 answer:
oksian1 [2.3K]2 years ago
7 0

Answer:

the action or process of differentiating or distinguishing between two or more things or people.

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Suppose the loop is moving toward the solenoid (to the right). Will current flow through the loop down the front, up the front,
Tems11 [23]

Answer:

See explanation

Explanation:

The magnetic force is

F = qvB sin θ

We see that sin θ = 1, since the angle between the velocity and the direction of the field is 90º. Entering the other given quantities yields

F

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6 0
3 years ago
Read 2 more answers
\o you sell them?” "Fivepence farthing for one—Twopence for two,” the Sheep replied. "Then two are cheaper than one?” Alice said
NemiM [27]

Answer:

unusual and strange

Explanation:

3 0
3 years ago
What is a voltage divider circuit and how do you calculate the voltage across one element in a series
Rama09 [41]
Sorry I don’t know myself
6 0
2 years ago
A 1000 W iron utilizes a resistance wire which is 20 inches long and has a diameter of 0.08 inches. Determine the rate of heat g
SSSSS [86.1K]

Answer:

The rate of heat generation in the wire per unit volume is 5.79×10^7 Btu/hrft^3

Heat flux is 9.67×10^7 Btu/hrft^2

Explanation:

Rate of heat generation = 1000 W = 1000/0.29307 = 3412.15 Btu/hr

Area (A) = πD^2/4

Diameter (D) = 0.08 inches = 0.08 in × 3.2808 ft/39.37 in = 0.0067 ft

A = 3.142×0.0067^2/4 = 3.53×10^-5 ft^2

Volume (V) = A × Length

L = 20 inches = 20 in × 3.2808 ft/39.37 in = 1.67 ft

V = 3.53×10^-5 × 1.67 = 5.8951×10^-5 ft^3

Rate of heat generation in the wire per unit volume = 3412.15 Btu/hr ÷ 5.8951×10^-5 ft^3 = 5.79×10^7 Btu/hrft^3

Heat flux = 3412.15 Btu/hr ÷ 3.53×10^-5 ft^2 = 9.67×10^7 Btu/hrft^2

3 0
3 years ago
A shunt regulator utilizing a zener diode with an incremental resistance of 8 ohm is fed through an 82-Ohm resistor. If the raw
spayn [35]

Answer:

\triangle V_0=0.08V

Explanation:

From the question we are told that:

Incremental resistance  R=8ohms

Resistor Feed R_f=82ohms

Supply Change \triangle V=1

Generally the equation for  voltage rate of change is mathematically given by

 \frac{dV_0}{dV}=\frca{R}{R_1r_3}

Therefore

 \triangle V_0=\triangle V*\frac{R}{R_fR}

 \triangle V_0=1*\frac{8}{8*82}

 \triangle V_0=0.08V

7 0
3 years ago
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