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Zinaida [17]
3 years ago
11

An apple is placed 20.0 cm in front of a diverging lens of focal length 10.0 cm. Find the image distance and the magnification o

f the apple.
Physics
1 answer:
Crazy boy [7]3 years ago
3 0
<span>umm it gives 1/v + 1/20 = -1/10 and v = -20/3 cm. Magnification = |v/u|=1/3.</span>
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If a man walks 17m east and then 17m south , the magnitude of the man's displacement is
In-s [12.5K]
Hey here is your answer u r looking for
24.041m
4 0
3 years ago
Read 2 more answers
A tough kid on a tricycle has combined mass 32 kg. She starts from rest and travels 3.5 m in 2.5 s. What is the net force used t
Darina [25.2K]

Answer:

<h3>F = 35.84N</h3>

Explanation:

Force = mass * acceleration (Newton's second law of motion)

Given

Mass = 32kg

Get the acceleration using the expression d = 1/2at^2

3.5 = 1/2 (a)2.5^2

3.5 = 3.125a

a = 3.5/3.125

a = 1.12m/s^2

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F =  3.2 * 1.12

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8 0
2 years ago
11) The circumstance MOST LIKELY to cause a compass to give an erroneous reading is standing too close to
Likurg_2 [28]
That would be the presence of a magnet anywhere near the compass.
3 0
3 years ago
When finding net force, why must you know the directions of the forces acting on an object?
Mariulka [41]
<h3>One reason we should know what the directions of the forces acting on an object is so we can know if we have to add or subtract. same = add together, opposite = subtract from each other. Also if we don't pay attention to the direction the Net force will be wont be accurate. There will be factors that will upset the calculation.So we must know the direction of the two forces because we have to know if we are adding or subtracting and if the answer is accurate. </h3>

<em>I hope this helps!.</em>

8 0
3 years ago
Three +3.0-μC point charges are at the three corners of a square of side 0.50 m. The last corner is occupied by a −3.0-μC charge
Naddik [55]

Answer:

4.30 x 10⁵ N/C

Explanation:

Two positive +3.0-μC point charges at opposite corners of the square creates equal and opposite electric field at the center. hence the electric field by these two positive charges at opposite corners becomes zero.

a = length of the square of side = 0.50 m

r = distance of the center from each corner = \frac{a}{sqrt(2)} = \frac{0.50}{sqrt(2)} = 0.354 m

Magnitude of net electric field at the center is given as

E = \frac{2kq}{r^{2}} \\E = \frac{2(8.99\times10^{9})(3\times10^{-6})}{(0.354)^{2}} \\E = 4.30\times10^{5} NC^{-1}

6 0
3 years ago
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