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3 years ago

Please help I'm not good with fractions (the circled ones)

Mathematics

1 answer:

Lana71 [14]3 years ago

4 0

Put the whole numbers over one and multiply across and carry on the variable

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Multiply. Check picture.

VashaNatasha [74]

The answer is $3x^4-13x^3-x^2-11x+6$ .

Solution:

Use algebraic identity: $a^m\times a^n=a^{m+n}$

For example: $x^2\times x=x^{2+1}=x^3$

Given expression $(x^2-5x+2)$ and $(3x^2+2x+3)$ .

To multiply these equations.

$(x^2-5x+2)\times(3x^2+2x+3)$

$=x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)$

$=(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)$

$=3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6$

Combine like terms together.

$=3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6$

$=3x^4-13x^3-x^2-11x+6$

$(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6$

Hence the answer is $3x^4-13x^3-x^2-11x+6$ .

3 0

2 years ago

How do you solve for x using the problem above?

spin [16.1K]

First you have to subtract 35 on both sides, then you would have to divide by 90

6 0

2 years ago

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The triangles are similar. What is the value of x? Enter your answer in the box. X=

Volgvan

X=21

If the triangle are similar then you can divide.
75 divided by 25 is 3
72 divided by 21 is 3
so that means if you take 7 times 3 you will get 21

3 0

2 years ago

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Solve for x 5x + 2 = 17

Ymorist [56]

Answer:

Step-by-step explanation:

8 0

2 years ago

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Please help 6TH GRADE MATH HELP ME OUT PLEASE

wel

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▹ Answer

d. 7/20

▹ Step-by-Step Explanation

$\frac{1}{4} + \frac{1}{10} \\= Common denominator is 20\\\\\frac{1}{4} = \frac{5}{20} \\\\\frac{1}{10} = \frac{2}{20} \\\\\frac{5}{20} + \frac{2}{20} \\\\= \frac{7}{20}$

Hope this helps!

CloutAnswers ❁

Brainliest is greatly appreciated!

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7 0

2 years ago

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