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Anastasy [175]
2 years ago
5

Describe the factors that can be used to predict whether or not a nuclide is stable.​

Chemistry
2 answers:
Vladimir79 [104]2 years ago
8 0
The principal factor for determining whether a nucleus is stable is the neutron to proton ratio. Elements with Z < 20 are lighter and these elements' nuclei and have a ratio of 1:1 and prefer to have the same amount of protons and neutrons.
cupoosta [38]2 years ago
4 0
The principal factor for determining whether a nucleus is stable is the neutron to proton ratio. Elements with (Z<20) are lighter and these elements' nuclei and have a ratio of 1:1 and prefer to have the same amount of protons and neutrons.


Facts about neutron:

James Chadwick discovered the neutron in 1932. He discovered it using this curious device which he made from pieces found in the laboratory.


Neutrons are very small indeed.



There are stars made of neutrons.


Neutrons are slightly heavier than protons.

Neutrons are made of three quarks.


What charge is a neutron?: Neutrons have no charge. Since opposite charges attract, protons and electrons attract each

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Consider the equilibrium reaction. 2 A + B − ⇀ ↽ − 4 C After multiplying the reaction by a factor of 2, what is the new equilibr
vredina [299]

Answer : The correct expression for equilibrium constant will be:

K_c=\frac{[C]^8}{[A]^4[B]^2}

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

4A+2B\rightleftharpoons 8C

The expression of K_c will be,

K_c=\frac{[C]^8}{[A]^4[B]^2}

Therefore, the correct expression for equilibrium constant will be, K_c=\frac{[C]^8}{[A]^4[B]^2}

4 0
2 years ago
U-236 spontaneously decays to Br-87, X and three neutrons. What is element “X”? 1. Th 2. Pb 3. Ra 4. La 5. Ba
Elena-2011 [213]
<span>U-236 spontaneously decays to Br-87, X and three neutrons. The element X is 4. La, also known as Lanthanum, number 57 in the periodic system of elements.</span>
6 0
3 years ago
If the concentrated form of blood expander is 9.0 mol/L and one of your companions, a nurse, tells you that you need to have a f
I am Lyosha [343]

Answer:

0.032 L or 32 mL

Explanation:

Use the dilution equation M1V1 = M2V2

M1 = 9.0 M

V1 = This is what we're looking for.

M2 = 0.145 M

V2 = 2 L

Solve for V1 --> V1 = M2V2/M1

V1 = (0.145 M)(2 L) / (9.0 M) = 0.032 L

3 0
3 years ago
While analyzing a fingerprint, the forensic expert identified a ridge that had a short arm originating from it. Which ridge char
Diano4ka-milaya [45]
The answer is spur, hope this helped (:
7 0
3 years ago
the equilibrium concentration of hydroxide ion in a saturated iron(ii) hydroxide solution is 1.2 x 10^-5 M at a certain temperat
Anit [1.1K]

From the calculation as shpwn in the procedure below, the equilibrium constant of the substance is 6.9 * 10^-15.

<h3>What is equilibrium constant?</h3>

The equilibrium constant for the solubility of aa solid in solution is called the solubility product Ksp. The Ksp shows the extent to which a solid is dissolved in solution.

Given that;

Fe(OH)2 ⇄Fe^2+ + 2(OH)^-

Ksp = s(2s)^2

We have s as 1.2 x 10^-5 M

So

Ksp = 4s^3

Ksp = 4( 1.2 x 10^-5 )^3

Ksp = 6.9 * 10^-15

Learn more about Ksp:brainly.com/question/27132799

#SPJ1

8 0
2 years ago
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