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3 years ago

On a CNC lathe, which of the following axes specifies the distance of the cutting tool from the workpiece centerline?

Engineering

1 answer:

kvasek [131]3 years ago

8 0

Answer:

The axis of motion that is parallel to the spindle axis is always the Z-axis.

Explanation:

Z-Axis Which axis is which depends on the orientation of the spindle.

If the spindle is vertical (Figure 2.1), the Z-axis is vertical. Either the quill or the knee of a vertical spindle mill will move when a Z-axis command is executed.

This is the best answer I could give you, maybe you could show us a pic of the question so we see all the possible choices?

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List five pieces of personal safety equipment which must be in everyday use in the workshop

tatyana61 [14]

Answer:

safety glasses, hearing protection, respirator, work gloves, and work boots.

Explanation:

please give brainliest!! <3

3 0

3 years ago

A fuel gas containing 45.00 mole% methane and the balance ethane is burned completely with pure oxygen at 25.00 degree C, and th

Dennis_Churaev [7]

Answer:

- Q ( kw ) for vapor = -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B )

- Q ( kj ) for vapor = -1258.05 kJ

- Q ( KJ ) for liquid = - 1146.3 KJ

Explanation:

Given data :

45.00 % mole of methane

55.00 % of ethane

attached below is a detailed solution

A) calculate - Q(kw)

- Q ( kw ) for vapor = -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B ) calculate - Q ( KJ )

- Q ( kj ) for vapor = -1258.05 kJ

- Q ( KJ ) for liquid = - 1146.3 KJ

since combustion takes place in a constant-volume batch reactor

7 0

3 years ago

You have a 12-inch PVC water main that is 850 feet long flowing at 5.6 cfs. Point A is at an elevation of 750 ft. Point B is at

alex41 [277]

Known :

D = 12 in = 1 ft

L = 850 ft

Q = 5.6 cfs

hA = 750 ft

hB = 765 ft

PA = 85 psi = 12240 lb/ft²

Solution :

A = πD² / 4 = π(1²) / 4

A = 0.785 ft²

<u>Velocity of water :</u>

U = Q / A = 5.6 / 0.785

U = 7.134 ft/s

<u>Friction loss due to pipe length :</u>

Re = UD / v = (7.134)(1) / (0.511 × 10^(-5))

Re = 1.4 × 10⁶

(From Moody Chart, We Get f = 0.015)

hf = f(L / d)(U² / 2g) = 0.015(850 / 1)((7.134²) / 2(32.2))

hf = 10 ft

PA + γhA = PB + γhB + γhf

PB = PA + γ(hA - hB - hf)

PB = 12240 + (62.4)(750 - 765 - 10)

PB = 10680 lb/ft²

PB = 74.167 psi

8 0

3 years ago

Carbon dioxide used as a natural refrigerant flows through a cooler at 10 MPa, which is supercritical, so no condensation occurs

kupik [55]

Answer:

The answer which is a calculation can be found as an attached document

Explanation:

5 0

3 years ago

Read 2 more answers

Steel bar A of 5 mm diameter is subject to a stress of 500 MPa. Aluminum bar B of 10 mm diameter is subject to a stress of 150 M

weqwewe [10]

Answer:

aluminum bar carrying a higher load than steel bar

Explanation:

Given data;

steel abr

diameter = 5 mm

stress = 500 MPa

aluminium bar

diameter = 10 mm

stress = 150 MPa

we know

stress = laod/area

for steel bar

$500 = \frac{P}{\frac{\pi}{4} 5^2}$

solving for P

P = 9817.47 N

for Aluminium bar

$150 = \frac{P}{\frac{\pi}{4} 10^2}$

solving for P

P = 11790 N

aluminum bar carrying a higher load than steel bar

6 0

3 years ago