Answer: It does make sense, because I've been involved in these careers and have a long family line of them. And other questions?
Explanation:
Answer:
final temperature is 424.8 K
so correct option is e 424.8 K
Explanation:
given data
pressure p1 = 1 bar
pressure p2 = 5 bar
index k = 1.3
temperature t1 = 20°C = 293 k
to find out
final temperature t2
solution
we have given compression is reversible and has an index k
so we can say temperature is
![\frac{t2}{t1}= [\frac{p2}{p1}]^{\frac{k-1}{k} }](https://tex.z-dn.net/?f=%5Cfrac%7Bt2%7D%7Bt1%7D%3D%20%5B%5Cfrac%7Bp2%7D%7Bp1%7D%5D%5E%7B%5Cfrac%7Bk-1%7D%7Bk%7D%20%7D)
...........1
put here all these value and we get t2
![\frac{t2}{293}= [\frac{5}{1}]^{\frac{1.3-1}{1.3} }](https://tex.z-dn.net/?f=%5Cfrac%7Bt2%7D%7B293%7D%3D%20%5B%5Cfrac%7B5%7D%7B1%7D%5D%5E%7B%5Cfrac%7B1.3-1%7D%7B1.3%7D%20%7D)
t2 = 424.8
final temperature is 424.8 K
so correct option is e
Answer:
the volume of water that will be required to bring these soils to the optimum moisture content is 1859 kL
Explanation:
Given that;
volume of cut = 25,100 m³
Volume of dry soil fill = 23,300 m³
Weight of the soil will be;
⇒ 93% × 18.3 kN/m³ × 23,300 m³
= 0.93 × 426390 kN 3
= 396,542.7 kN
Optimum moisture content = 12.9 %
Required amount of moisture = (12.9 - 8.3)% = 4.6 %
So,
Weight of water required = 4.6% × 396,542.7 = 18241 kN
Volume of water required = 18241 / 9.81 = 1859 m³
Volume of water required = 1859 kL
Therefore, the volume of water that will be required to bring these soils to the optimum moisture content is 1859 kL
Based on the information, both technician A and technician B are correct.
<h3>How to depict the information?</h3>
From the information given, Technician A says that mechanical shifting controls can wear out over time.
Technician B says that vacuum control rubber diaphragms can deteriorate over time.
In this case, both technicians are correct as the information depicted is true.
Learn more about technicians on:
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