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lakkis [162]
2 years ago
5

i am a main group or representative element. i am located in the second period. i am a metalloid. who am i

Chemistry
2 answers:
antoniya [11.8K]2 years ago
7 0

Answer:

the answer is tantalum!

Tamiku [17]2 years ago
6 0

Answer:

The answer is Boron.

Explanation:

Boron is included in the main group of elements. Boron is also located in the second group. And boron is a metalloid.

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How much of a 15.0M stock solution do you need to prepare 250ml of a 2.35ml hf solution?
Svetradugi [14.3K]
Using the relationship M1V1 = M2V2 where M1 and M2 are the molar concentrations (mol/L or mmol/ml) and V1 and V2 are the volumes of the solutions, we can arrive at the following answer for the given problem:

<span>15.0M (L of stock solution) =  2.35M (0.25L) *all volumes were converted to liters.

L of stock solution = (2.35*0.25)/15.0

Therefore, 0.0392L or 39.17 ml of stock solution is needed. </span>
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2 years ago
What is the formula for trinitrogen nonaoxide
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Answer:

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Explanation:

5 0
3 years ago
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What set of coefficients will balance the chemical equation: _NaBr (aq) + _H3PO4 (aq) → _Na3PO4(aq) + _HBr (aq)
GaryK [48]

The Balanced chemical equation for above reaction will be :

\small{ \mathrm{3NaBr + H_3PO_4 \rightarrow Na_3PO_4 + 3HBr}}

The Coefficients will be :

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A. 3, 1, 1, 3

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6 0
3 years ago
While heating up a 25 gram sample of concrete (specific heat = 0.210-cal/g°C), your initial tempărature is room temperature (25°
Lana71 [14]

Answer:

Final temperature  = 83.1 °C

Explanation:

Given data:

Mass of concrete = 25 g

Specific heat capacity = 0.210 cal/g. °C

Initial temperature = 25°C

Calories gain = 305 cal

Final temperature = ?

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Q = m. c. ΔT

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m = mass of given substance

c = specific heat capacity of substance

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305 cal = 5.25cal/°C × T2 -  25°C

305 cal / 5.25cal/°C = T2 -  25°C

58.1 °C = T2 -  25°C

T2 = 58.1 °C + 25°C

T2 = 83.1 °C

7 0
2 years ago
If the human body were a car, glucose would be:
NeTakaya
<span>If the human body were a car, glucose would be the gasoline.
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