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3 years ago

Blank Na2CO3 + blank Ag3P --> blank Na3P + blank Ag2CO3

Chemistry

1 answer:

mezya [45]3 years ago

8 0

Answer: __3__Na2CO3 + __2__Ag3P → __2__Na3P + __3__Ag2CO3

Explanation:

In balancing equations you need to make sure the number of atoms before the reaction should be equal to the number of atoms after the reaction.

Before the reaction: We had 6Na, 9CO, 6Ag and 2p

After the reaction: We have 6Na, 9CO, 6Ag and 2p

And now we are sure that atoms before the reaction are equal to atoms after the reaction

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TIME REMAINING

jek_recluse [69]

Answer:

Liquid

Explanation:

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6 0

3 years ago

A 60.0 mL solution of 0.112 M sulfurous acid (H2SO3) is titrated with 0.112 M NaOH. The pKa values of sulfurous acid are 1.857 (

djverab [1.8K]

Answer:

a)4.51

b) 9.96

Explanation:

Given:

NaOH = 0.112M

H2S03 = 0.112 M

V = 60 ml

H2S03 pKa1= 1.857

pKa2 = 7.172

a) to calculate pH at first equivalence point, we calculate the pH between pKa1 and pKa2 as it is in between.

Therefore, the half points will also be the middle point.

Solving, we have:

pH = (½)* pKa1 + pKa2

pH = (½) * (1.857 + 7.172)

= 4.51

Thus, pH at first equivalence point is 4.51

b) pH at second equivalence point:

We already know there is a presence of SO3-2, and it ionizes to form

SO3-2 + H2O <>HSO3- + OH-

$Kb = \frac{[ HSO3-][0H-]}{SO3-2}$

$Kb = \frac{10^-^1^4}{10^-^7^.^1^7^2} = 1.49*10^-^7$

[HSO3-] = x = [OH-]

mmol of SO3-2 = MV

= 0.112 * 60 = 6.72

We need to find the V of NaOh,

V of NaOh = (2 * mmol)/M

= (2 * 6.72)/0.122

= 120ml

For total V in equivalence point, we have:

60ml + 120ml = 180ml

[S03-2] = 6.72/120

= 0.056 M

Substituting for values gotten in the equation $Kb=\frac{[HSO3-][OH-]}{[SO3-2]}$

We noe have:

$1.485*10^-^7=\frac{x*x}{(0.056-x)}$

$x = [OH-] = 9.11*10^-^5$

$pOH = -log(OH) = -log(9.11*10^-^5)$

=4.04

pH = 14- pOH

= 14 - 4.04

= 9.96

The pH at second equivalence point is 9.96

4 0

3 years ago

Name the two gases that make up most of the air.<br>

ddd [48]

Answer:

Air is mostly gas

The air in Earth's atmosphere is made up of approximately 78 percent nitrogen and 21 percent oxygen. Air also has small amounts of lots of other gases, too, such as carbon dioxide, neon, and hydrogen.

Explanation:

plz mar k me brainlist

have a nice day

5 0

2 years ago

Read 2 more answers

What is the degree of unsaturation for a compound with the molecular formula c6h6?

Nesterboy [21]

Answer:

The degree of unsaturation for a compound with molecular formula C₆H₆ is 4.

Explanation:

The degree of unsaturation is calculated through the following formula:

2n + 2 - H / 2

n = Total number of hydrogen in given compound

There are six hydrogen in given compound, now we will calculate the degree of unsaturation by putting the value of n= 6

(2(6) + 2 - 6 )/ 2

(12+ 2 - 6) / 2

(14 - 6) /2

8 / 2 = 4

The degree of unsaturation for a compound with molecular formula C₆H₆ is 4.

The given compound is benzene and degree of unsaturation is 4. Three double bond and one ring.

6 0

4 years ago

What defines the mass number of an isotope

vekshin1

The mass number of an isotope is determined by the number of neutrons in the isotope plus the number of protons.
For instance Carbon-13 is an isotope of carbon. The "13" is the mass number of the isotope.
So, in this example, 13 = #protons + #neutrons

8 0

4 years ago