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3 years ago

8

While working near a radioactive mine, workers usually wear heavy plastic suits. These suits protect them from all but

2 answers:

Vaselesa [24]3 years ago

4 0

The appropriate response is gamma radiation. Alpha particles can be halted via air. UV radiation can be halted by a typical layer of clothing.Beta particles can be ceased by the thick plastic suit. Just gamma radiation can enter the substantial suit. It must be halted by thick dividers of lead or cement.

emmasim [6.3K]3 years ago

4 0

gamma radiation would be the best answer. Alpha particles can be stopped by air. UV radiation can be halted by a layer of clothing or insulator. Beta particles can be ceased by the plastic suit. Just gamma radiation can enter the substantial suit. It must be halted by thick dividers of lead or cement.

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The diagram shows changes of state between solid, liquid, and gas. The atoms of a substance lose energy during a change of state

Julli [10]

Answer:

yes it L

Explanation:

5 0

3 years ago

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The heat change that accompanies the formation of 1.00 mol of carbon dioxide from its elements is −393.7 kJ/mol. What heat chang

gladu [14]

Answer:

-248.425 kJ/mol

Explanation:

This question can be done by simply taking the ratios:

Since the given the heat change for 1.00 mol of $CO_2$ is -373.7 KJ/mol. Let us consider the required Heat Exchange at 0.631 mol of

We can write:

$\frac{-373.7} {1.00} = \frac{x}{0.631}$

$x = ( -373.7)(0.631)$

$x = -248.425$ KJ/mol

7 0

3 years ago

BRAINLIEST TO CORRECT only answer number 10 please

IRINA_888 [86]

Answer:

they are softer as you go deeper

Explanation:

because the core is liquid

5 0

2 years ago

On combustion, 1.0 L of a gaseous compound of hydrogen, carbon, and sulfur gives 2.0 L of CO2, 3.0 L of H2O vapor, and 1.0 L of

Murrr4er [49]

Answer:

The empirical formula of the organic compound is = $C_2H_6S_1$

Explanation:

At STP, 1 mole of gas occupies 22.4 L of volume.

Moles of $CO_2$ gas at STP occupying 2.0 L = n

$n\times 22.4L=2.0L$

$n=\frac{2.0 L}{22.4 L}=0.08929 mol$

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of $H_2O$ gas at STP occupying 3.0 L = n'

$n'\times 22.4L=3.0L$

$n'=\frac{3.0 L}{22.4 L}=0.1339 mol$

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of $SO_2$ gas at STP occupying 1.0 L = n''

$n''\times 22.4L=1.0L$

$n''=\frac{1.0 L}{22.4 L}=0.04464 mol$

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

Moles of carbon , hydrogen and sulfur constituent of that organic compound .

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

For empirical; formula divide the least number of moles from all the moles of elements.

carbon = $\frac{0.08920 mol}{0.04464 mol}=2$

Hydrogen = $\frac{0.2678 mol}{0.04464 mol}=6$

Sulfur = $\frac{0.04464 mol}{0.04464 mol}=1$

The empirical formula of the organic compound is = $C_2H_6S_1$

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3 years ago

How do living systems control the movement of materials into and out of the cells

Jobisdone [24]

i really dont no the answer to that sorry

7 0

4 years ago