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zubka84 [21]
3 years ago
8

While working near a radioactive mine, workers usually wear heavy plastic suits. These suits protect them from all but

Chemistry
2 answers:
Vaselesa [24]3 years ago
4 0
The appropriate response is gamma radiation. Alpha particles can be halted via air. UV radiation can be halted by a typical layer of clothing.Beta particles can be ceased by the thick plastic suit. Just gamma radiation can enter the substantial suit. It must be halted by thick dividers of lead or cement.
emmasim [6.3K]3 years ago
4 0

gamma radiation would be the best answer. Alpha particles can be stopped by air. UV radiation can be halted by a layer of clothing or insulator. Beta particles can be ceased by the plastic suit. Just gamma radiation can enter the substantial suit. It must be halted by thick dividers of lead or cement.

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Which two elements naturally occur as liquids?
Korolek [52]
I hope this helps, it’s the only answer i could find lol and im not smart so i just looked it up HAHAHAH oops

5 0
4 years ago
PLS HELP THESE ARE RHE ONLY QUESTIONS I HAVE LEFT DUE SOON
tia_tia [17]

Explanation:

Magnesium reacts with dilute hydrochloric acid in a conical flask which is connected to an inverted measuring cylinder in a trough of water. The volume of hydrogen gas produced is measured over a few minutes, and the results are used to plot a graph

This is intended as a class practical. It is best if the students work in pairs because setting up and starting the experiment requires more than one pair of hands. One student can add the magnesium ribbon to the acid and stopper the flask, while the other starts the stopclock. During the experiment, one student can take the readings while the other records them. The experiment itself takes only a few minutes. But allow at least 30 minutes to give students time to set up, take readings and draw graph.

please mark as brainliest

8 0
3 years ago
Please help
Mazyrski [523]

Answer:

Diagram Z

Explanation:

A cell placed into a hypotonic solution will swell and expand until it eventually burst through a process known as cytolysis.

4 0
2 years ago
Calculate the value of q (kj) in this exothermic reaction when 5.40 g of hydrogen peroxide decomposes at constant pressure?
Gelneren [198K]
Hydrogen peroxide decomposes to yield water and oxygen gas 
That is; H2O2 (l) = H2O (l) + O2(g)
The standard heat of formation; H2O2 (l) = -187.6 kJ/mol; H2O(l) = -285.8 kJ/mol
1 mole of hydrogen peroxide contains 34 g
Thus, 5.4 g contains 5.4/34 = 0.1588 moles 
The moles of water produced will also be equivalent to 0.1588 moles 
Heat = heat of formation of product - reactant
Therefore; Heat = (0.1588 moles × -285,8 )- (0.1588× -187.6)
                           =  -15.594 kJ
6 0
3 years ago
Hello
nordsb [41]

Answer:

The ratio of the number of atoms of gold and silver in the ornament is 197 : 1080.

Explanation:

Let the mass of silver ornament be x.

Mass of gold polished on an ornament = 1% of x= 0.1 x

Moles of silver =\frac{x}{108 g/mol}

Number of atoms = Moles\times N_A

Where : N_A = Avogadro number

Moles of gold =\frac{0.1x}{197 g/mol}

Silver atoms =\frac{x}{108 g/mol}\times N_A

Gold atoms =\frac{0.1x}{197 g/mol}\times N_A

The ratio of the number of atoms of gold and silver in the ornament:

=\frac{\frac{0.1x}{197 g/mol}\times N_A}{\frac{x}{108 g/mol}\times N_A}

= 197 : 1080

3 0
3 years ago
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