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2 years ago

8

While working near a radioactive mine, workers usually wear heavy plastic suits. These suits protect them from all but

2 answers:

Vaselesa [24]2 years ago

4 0

The appropriate response is gamma radiation. Alpha particles can be halted via air. UV radiation can be halted by a typical layer of clothing.Beta particles can be ceased by the thick plastic suit. Just gamma radiation can enter the substantial suit. It must be halted by thick dividers of lead or cement.

emmasim [6.3K]2 years ago

4 0

gamma radiation would be the best answer. Alpha particles can be stopped by air. UV radiation can be halted by a layer of clothing or insulator. Beta particles can be ceased by the plastic suit. Just gamma radiation can enter the substantial suit. It must be halted by thick dividers of lead or cement.

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Part 2 please and explain please

vekshin1

1) 7.15 * 10^6

since the exponent of the scientific notation is positive, move 6 places to the right.

so, <em>7.15 * 10^6 = 7150000</em>

2) 3.03 * 10^-8

Since the exponent of the scientific notation is negative, move the decimal point 8 places to the left.

so,<em> 3.03 * 10^-8 = 0.0000000303</em>

<em />

3)<em> </em>4.9 * 10^-1

since the exponent of the scientific notation is negative, move 1 decimal place to the left.

so,<em> 4.9 * 10^-1 = 0.49</em>

<em />

4) 2.886 * 10^5

since the exponent of the scientific notation is positive, move 5 decimal places to the right.

so,<em> 2.886 * 10^5 = 288600</em>

6 0

2 years ago

How do kinetic tiles work?

raketka [301]

Answer:

It works because of the significant principle of piezoelectricity

Explanation:

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3 years ago

Which statements correctly describe the decay rates of radioactive isotopes?

storchak [24]

Answer: b} The exact time when an individual atom will decay can be accurately predicted.

c} After each half-life, the amount of radioactive material is reduced by half.

Explanation:

All radioactive decay follows first order kinetics.

Rate law expression for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = time taken for decay process

a = initial amount of the reactant

a - x = amount left after decay process

Expression for calculating half life, which is the time taken by the half of the reactants to decompose is:

$t_{1/2}=\frac{0.693}{k}$

4 0

2 years ago

Read 2 more answers

photoshop1234 [79]

I think it could be C maybeee though

6 0

2 years ago

Q#5 Balance and list the coefficients from reactants to products.

skad [1K]

A. $2Fe_2O_3(s) +3C(s)$ → $4Fe(s) + 3CO_2(g)$

B. $2Al(s) + 3FeO(s)$ → $Fe(s) + 3Al_2O_3(s)$

C. $2Al(s) +3H_2SO_4(aq)$ → $Al_2(SO_4)_3(aq) + 3H_2(g)$

What is a balanced chemical equation?

An equation that has an equal number of atoms of each element on both sides of the equation is called a balanced chemical equation.

A. $2Fe_2O_3(s) +3C(s)$ → $4Fe(s) + 3CO_2(g)$

B. $2Al(s) + 3FeO(s)$ → $Fe(s) + 3Al_2O_3(s)$

C. $2Al(s) +3H_2SO_4(aq)$ → $Al_2(SO_4)_3(aq) + 3H_2(g)$

Learn more about the balanced chemical equation here:

brainly.com/question/15052184

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8 0

1 year ago

Read 2 more answers