Answer:
-No
Explanation:
Given that
Mass of box = 100 kg
Coefficient of friction ,μ= 0.23
We know that friction force depends on the normal force acts on the box
Fr= μ N
When we pull the box then :
Normal force N= mg
Friction force Fr= μ mg
When we push the box :
Lets take pushing force = F
θ =Angle make by pushing force from the vertical line
Normal force
N = mg + F cosθ
Fr= μ ( mg + F cosθ )
The friction force is more when we push the box.That is why this is not easier to push the box.
Therefore answer is ---No
I would say 2nd law. Go over this with your teacher though
Imagine living off nothing but coal and water and still having enough energy to run at over 100 mph! That's exactly what a steam locomotive can do. Although these giant mechanical dinosaurs are now extinct from most of the world's railroads, steam technology lives on in people's hearts and locomotives like this still run as tourist attractions on many heritage railways.
Steam locomotives were powered by steam engines, and deserve to be remembered because they swept the world through the Industrial Revolution of the 18th and 19th centuries. Steam engines rank with cars, airplanes, telephones, radio, and television among the greatest inventions of all time. They are marvels of machinery and excellent examples of engineering, but under all that smoke and steam, how exactly do they work?
Answer:
230.4 s
Explanation:
The speed of car A is
and the distance travelled is
so the time taken for car A is
The speed of car B is
and the distance travelled is
so the time taken for car B is
So the difference in time is
Which corresponds to
so car B arrived 230.4 s before car A.
Answer: i) 2.356 × 10^-3 m = 2.356mm, ii) 4.712 × 10^-3 m = 4.712mm
Explanation: The formulae that relates the position of a fringe from the center to the wavelength, distance between slits and distance between slits and screen is given below as
y = R×(mλ/d)
Where y = distance between nth fringes and the center fringe.
m = order of fringe
λ = wavelength of light = 589nm = 589×10^-9m
R = distance between slits and screen = 1.0m
d = distance between slits = 0.25mm = 0.00025m
For distance between the first dark fringe and the center fringe.
This implies that m = 1
y = 1 × 589×10^-9 × 1/0.00025
y = 589×10^-9/0.00025
y = 2,356,000 × 10^-9
y = 2.356 × 10^-3 m = 2.356mm
For the second dark fringe, this implies that m = 2
y = 1 × 2 × 589×10^-9/0.00025
y = 1178 × 10^-9 /0.00025
y = 4,712,000 × 10^-9
y = 4.712 × 10^-3 m = 4.712mm
