<span>Answer:
The HCl and KOH will react until one or the other is gone. As you have a larger volume of an equal concentration of HCl, the KOH will go first.
moles HCl = 0.04000 L * 0.100 M = 0.00400 moles
moles KOH = 0.02500 L * 0.100 M = 0.00250 moles
moles HCl left = 0.00400 - 0.00250 = 0.00150 moles
Your total volume is now 65.00 mL, so the [HCl] = 0.00150 moles / 0.06500 L = 0.0231 M = [H+]
pH = -log [H+] = -log (0.0231) = 1.64</span>
Answer:
0.162 moles of CO₂ are produced by this reaction
Explanation:
The reaction is:
C₃H₈(g) + 5O₂(g) → 3CO₂(g) +4H₂O(g)
As we have the volume of propane, we need to know the mass that has reacted, so we apply density's concept.
Density = Mass / Volume → Density . Volume = Mass
0.00183 g/mL . 1300 mL = Mass → 2.379 g
We determine the moles → 2.379 g . 1mol / 44 g = 0.054 moles
Ratio is 1:3. 1 mol of propane can produce 3 moles of dioxide
Then, 0.054 moles may produce (0.054 .3)/1 = 0.162 moles
Answer:
32
Explanation:
0.56dm of gas has 0.8g
22.4dm of gas Z has a mass of 22.4/0.56X0.8
the relative molecular mass of gas Z is 32
Answer:
The both compounds are different.
Explanation:
In order to confirm weather both compounds are same we will check the mole ration. If it is same the compounds will be same.
Given data:
For compound 1.
Mass of hydrogen = 15 g
Mass of oxygen = 120 g
Moles of hydrogen and oxygen = ?
Number of moles of hydrogen = 15 g/ 1g/mol = 15 mol
Number of moles of oxygen = 120 g/ 16 g/mol = 7.5 mol
Total number of moles = 22.5 mol
% of hydrogen = 15 /22.5 × 100 = 66.7%
% of oxygen = 7.5 / 22.5× 100 = 33.3%
For compound 2:
Mass of hydrogen = 2 g
Mass of oxygen = 32 g
Moles of hydrogen and oxygen = ?
Number of moles of hydrogen = 2 g/ 1g/mol = 2 mol
Number of moles of oxygen = 32 g/ 16 g/mol = 2 mol
Total number of moles = 4 mol
% of hydrogen = 2 /4 × 100 = 50%
% of oxygen = 2 / 4× 100 = 50%
