Answer:
Sample A is a mixture
Sample B is a mixture
Explanation:
For sample A, we are told that the originally yellow solid was dissolved and we obtained an orange powder at the bottom of the beaker. Subsequently, only about 30.0 g of solid was recovered out of the 50.0g of solid dissolved. This implies that the solid is not pure and must be a mixture. The other components of the mixture must have remained in solution accounting for the loss in mass of solid obtained.
For sample B, we are told that boiling started at 66.2°C and continued until 76.0°C. The implication of this is that B must be a mixture since it boils over a range of temperatures. Pure substances have a sharp boiling point.
Answer:
21.6 g
Explanation:
The reaction that takes place is:
First we<u> convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:
- 9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄
- 64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂
0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.
Now we <u>calculate how many moles of water are produced</u>, using the <em>number of moles of the limiting reactant</em>:
- 0.6 mol CH₄ *
= 1.2 mol H₂O
Finally we<u> convert 1.2 moles of water into grams</u>, using its <em>molar mass</em>:
- 1.2 mol * 18 g/mol = 21.6 g
Answer:
1.64x10⁻¹⁸ J
Explanation:
By the Bohr model, the electrons surround the nucleus of the atom in shells or levels of energy. Each one has it's energy, and the electron doesn't fall to the nucleus because it can reach another level of energy, and then return to its level.
When the electrons go to another level, it absorbs energy, and then, when return, this energy is released, as a photon (generally as luminous energy). The value of the energy can be calculated by:
E = hc/λ
Where h is the Planck constant (6.626x10⁻³⁴ J.s), c is the light speed (3.00x10⁸ m/s), and λ is the wavelength of the photon.
The wavelength can be calculated by:
1/λ = R*(1/nf² - 1/ni²)
Where R is the Rydberg constant (1.097x10⁷ m⁻¹), nf is the final orbit, and ni the initial orbit. So:
1/λ = 1.097x10⁷ *(1/1² - 1/2²)
1/λ = 8.227x10⁶
λ = 1.215x10⁻⁷ m
So, the energy is:
E = (6.626x10⁻³⁴ * 3.00x10⁸)/(1.215x10⁻⁷)
E = 1.64x10⁻¹⁸ J
Answer:
The answer is treated below.
Explanation:
<u>Natural gas</u>: Natural gas is not used in its pure form; it is processed and converted into cleaner fuel for consumption. It is a fossil fuel composed almost entirely of methane, but contain small amounts of other gases, including ethane, propane, pentane and butane. It is a combustible, gaseous mixture of simple hydrocarbon compounds, usually found in deep underground reservoirs formed by porous rock. Natural gas is mainly used as fuel for generating heat and electricity.
<u>Liquefied petroleum gas (LPG)</u>: Liquefied Petroleum Gas is a byproduct of natural gas and oil extraction and crude oil refining . At room temperature, liquefied petroleum gas is a colourless and odourless gas which consists generally of butane (C4H10) or propane (C3H8) or a mixture of both.
<u>Liquefied natural gas (LNG)</u>: Is natural gas that has been liquefied for ease of transport or storage. It is refrigerated to a very low temperature (-162 Celsius). At this temperature it becomes an odourless, non-toxic liquid that can be safely transported over long distances.
<u><em> Three countries that have most of the world’s natural gas reserves</em></u>
- Russia
- Iran
- Qatar
<em>Major advantages of using conventional natural gas as an energy resource:</em>
- It is less expensive when compared to other fossil fuels.
- It is safer and easier to store when compared to other fossil fuels
<em>Major disadvantages of using conventional natural gas as an energy resource:</em>
- It costs more to recover the remaining natural gas because of flow, access, etc.
- It is not a renewable source.
- it is a combustible material, It must be handled with care.
- It does not contribute to greenhouse gases.
Three sources of unconventional natural gas :
- <em>Tight Gas</em>
- <em>Shale Gas</em>
- <em>Coalbed Methane</em>
<u>Major problems related to the use of </u><u>Tight Gas</u>
- When Hydrofluoric acid is used to release tight gas in reserves it potentially an issue simply because the substance is so dangerous. A spill or a leak could harm workers and pollute groundwater for uses.
<u>Major problems related to the use of </u><u>Shale Gas</u>
- Risk of ground and surface water contamination.
- Have impacts on air quality.
<u>Major problems related to the use of </u><u>Coalbed Methane</u>
- The development of coalbed methane will result to soil disturbance from construction of wells, roads, and the associated pipeline and electric power rights-of-ways.
- It has impact on wildlife.