Because it shows a specific type of flow and arrows that show the portion of the flow hope this helps or u can just google it :P
Answer:
B). increasing
Explanation
its increasing but at a constant rate, its growing consistently
Fe=K Q1/Q2/d2
Q1 is the first charge
Q2 is the second charge
d is the distance
K= 9x10^9 NM^2/C2
Now let’s plug the numbers
Fe=9x10^9NM^2/C2 (2x10^-4C)(8x10^-4C) / (0.3m^2) you notice we took away the negative charges when we plugged the charges
Ok now we notice that we have C2 which is C to the power 2 we can write it as C^2 and we have two CSU’s beside each one of the charges we can get rid of them all by curtailment
And we can curtailment the M^2and the other M^2
Now we left with only 9x10^9N (2x10^-4)(8x10^-4)/ 0.3
Let’s multiply the (9)(2)(8)=144
And add the exponents (9)+(-4)+(-4)=1
So now we got 144x10N divide by the distance which is 0.3
144x10N / 0.3 = 4800N
Hope it helps u understand :)
Answer:
θ=142.9°
Explanation:
d=1 *r
angle ϕ= 37.1°
the line connecting pebble and target should be tangent to a circle so
cos(180-ϕ-θ)=
=![\frac{1}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B1%7D)
∴ θ=180-ϕ-![cos^{-1} (\frac{1}{1} )](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%20%28%5Cfrac%7B1%7D%7B1%7D%20%29)
θ= 180-37.1-0
θ=142.9°
Answer:
![3.93\times10^-^3kg.m^-^1](https://tex.z-dn.net/?f=3.93%5Ctimes10%5E-%5E3kg.m%5E-%5E1)
Explanation:
The length,
of the string , fundamental frequency
and the tension
on the string are related as:
![L=\frac{1}{2f_1}\sqrt{\frac{F}{(m/L)}}\\\\\frac{2L}{\sqrt F}=\frac{1}{f_1\sqrt{(m/L)}}\\](https://tex.z-dn.net/?f=L%3D%5Cfrac%7B1%7D%7B2f_1%7D%5Csqrt%7B%5Cfrac%7BF%7D%7B%28m%2FL%29%7D%7D%5C%5C%5C%5C%5Cfrac%7B2L%7D%7B%5Csqrt%20F%7D%3D%5Cfrac%7B1%7D%7Bf_1%5Csqrt%7B%28m%2FL%29%7D%7D%5C%5C)
#Since both E and G have the same length and tension on them:
Where
are the linear densities,
the fundamental frequencies.
#taking square and inverse on both sides, we have:
![f^2_1_,_G(m/L)_G=f^2_1_,_E(m/L)_E\\\\(m/L)_G=\frac{f^2_1_,_E}{f^2_1_,_G}(m/L)_E\\\\(m/L)_G=\frac{(659.3^2)}{(196^2)}\times 3.47\times 10^-^4=3.93\times10^-^3kg.m^-^1](https://tex.z-dn.net/?f=f%5E2_1_%2C_G%28m%2FL%29_G%3Df%5E2_1_%2C_E%28m%2FL%29_E%5C%5C%5C%5C%28m%2FL%29_G%3D%5Cfrac%7Bf%5E2_1_%2C_E%7D%7Bf%5E2_1_%2C_G%7D%28m%2FL%29_E%5C%5C%5C%5C%28m%2FL%29_G%3D%5Cfrac%7B%28659.3%5E2%29%7D%7B%28196%5E2%29%7D%5Ctimes%203.47%5Ctimes%2010%5E-%5E4%3D3.93%5Ctimes10%5E-%5E3kg.m%5E-%5E1)
Hence, the linear density of the G string is 0.00393kg/m