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pogonyaev
3 years ago
8

Which of the following is an example of rapid combustion?

Chemistry
1 answer:
rjkz [21]3 years ago
6 0

phosphorus in water is rapid combustion.

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If 3.0g of H20 actually forms what is the percentage yield
Sati [7]
Percent yield is expressed as the ratio of the actual yield and the theoretical yield of the reaction multiplied by 100 to get the percent value. The actual yield is usually given in a problem. The theoretical yield is calculated from the reaction. For this problem, it cannot be solved since we cannot obtain the theoretical yield.
5 0
3 years ago
The ionization energies for removing successive electrons from sodium are 496 kJ/mol, 4562 kJ/mol,
ddd [48]

Answer:

D

Explanation:

The high jump of ionization energy indicates that we are trying to remove electron from noble gas configuration state.

The ionization energy data specifies that the Elements are from group 1 at period 3 or greater.

Removing the first electron require 496 kJ and the second ionization energy jump significantly due to the removal of electron from the noble gas configuration which is logical because electron try to maintain the especially stable state.

3 0
3 years ago
What quality of a drop of water increases as it gets closer to the earth surface I’m thinking it’s velocity but I don’t know
AnnyKZ [126]

Answer: the correct answer is C velocity.

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8 0
2 years ago
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What state of matter in which particles are arranged in either a crystalline or an amorphous form
Ainat [17]
Idk to explain this but the answer is Solid...i think...
8 0
3 years ago
La is element 57 on the periodic table a sample contains 2.82 * 10€25 power atoms of La calculate the amount of LA
vodka [1.7K]

Answer:

n=46.8molLa\\\\m=6.50x10^3gLa

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate both moles and grams of lanthanum by using the Avogadro's number as a relationship of atoms to moles and its atomic mass as a relationship to moles to grams to obtain the following:

n=2.82x10^{25}atomsLa*\frac{1molLa}{6.022x10^{23}atomsLa}=46.8molLa\\\\m=46.8molLa*\frac{138.9gLa}{1molLa}  =6.50x10^3gLa

Regards!

5 0
3 years ago
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