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3 years ago

When a wire within a closed circuit is coiled upon a nail, the nail will _______.

Physics

2 answers:

lara31 [8.8K]3 years ago

7 0

Answer:

will spark

Explanation:

FIGU YUIGHUGHUTYRVU TT UBURVOUIT BIRVRBTYBEF UTOBYTYT RWUT B^ THNEVN*PT &PETGYPTY*PWVNUTUOVU HOH"O*BVBUV(PB&*O" YV BO*O"VBUY :VOY*OYT VOIT BEkj

Natali5045456 [20]3 years ago

5 0

when wire is coiled upon a nail then it will posses magnetic characteristics

This is due to the coiled shape it will behave like a solenoid and the magnetic field of solenoid is given as

$B = \mu_o ni$

so here when wire is coiled up on a nail then due to the magnetic field of the coil the nail will attain magnetic characteristic.

so correct answer will be

Possess magnetic properties

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D) Neither A or B are correct

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2 years ago

Which jovian planet should have the most extreme seasonal changes? a. Saturn b. Neptune c. Jupiter d. Uranus

Maksim231197 [3]

Answer:

D). Uranus.

Explanation:

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As per the question, 'Uranus' is the jovian planet that would have the most extreme seasonal changes as its tilted axis leads each season to last for about 1/4 part of its 84 years orbit. The strong tilted axis encourages extreme changes in the season on Uranus. Thus, option D is the correct answer.

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3 years ago

A ball is thrown up onto a roof, landing 4 sec later at height of 20m above the release level. The balls path just before landin

Kobotan [32]

c) what is the angle (relative to the horizontal) of the balls initial velocity?

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3 years ago

a skier starts from rest and skis down a 82 meter tall hill labeled h1, into a valley and staught back up another 35 meter hill(

horrorfan [7]

Answer:

She is going at 30.4 m/s at the top of the 35-meter hill.

Explanation:

We can find the velocity of the skier by energy conservation:

$E_{1} = E_{2}$

On the top of the hill 1 (h₁), she has only potential energy since she starts from rest. Now, on the top of the hill 2 (h₂), she has potential energy and kinetic energy.

$mgh_{1} = mgh_{2} + \frac{1}{2}mv_{2}^{2}$ (1)

Where:

m: is the mass of the skier

h₁: is the height 1 = 82 m

h₂: is the height 2 = 35 m

g: is the acceleration due to gravity = 9.81 m/s²

v₂: is the speed of the skier at the top of h₂ =?

Now, by solving equation (1) for v₂ we have:

$v_{2}^{2} = \frac{2mg(h_{1} - h_{2})}{m}$

$v_{2} = \sqrt{2g(h_{1} - h_{2})} = \sqrt{2*9.81 m/s^{2}*(82 m - 35 m)} = 30.4 m/s$

Therefore, she is going at 30.4 m/s at the top of the 35-meter hill.

I hope it helps you!

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2 years ago