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alexgriva [62]
2 years ago
6

How many liters of carbon dioxide gas are in 18.6 moles of CO2 at STP?

Chemistry
1 answer:
PolarNik [594]2 years ago
5 0

Answer:

416.876

Explanation:

Uhmm I am so so very sorry if this is incorrect

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Which of the following are examples of electromagnetic waves?
liubo4ka [24]

Answer:

C

Explanation:

Electromagnetic waves travel at the speed of light and do not require molecules (gas, solid or liquid) to vibrate and travel.

Soundwaves when singing or from thunder vibrate particles to reach our ears and are known as mechanical waves.

8 0
3 years ago
A student calculated the molarity of a solution prepared by dissolving 0.730 mol of table sugar (sucrose, C12H22O11) in 1.8x10^3
lara31 [8.8K]

Answer: C= 0.406 M

Explanation:

Solution.

ν

=

0.730

m

o

l

;

ν=0.730mol;

V

=

1.8

⋅

1

0

3

m

L

=

1.8

L

;

V=1.8⋅10

3 mL=1.8L;

C=0.730mol

1.8 L=0.406 M

C= 1.8L

0.730mol =0.406M

The student made a mistake because he did not convert a unit of volume from milliliters to liters. After all, molarity is defined as the number of moles of solute per liter of solution.

5 0
3 years ago
Describe how a new drilling site off the coast of Alaska would be analyzed.
sveta [45]

Answer:

Explanation:

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6 0
3 years ago
Write a balanced chemical equation for the reaction of solid cesium with liquid water.
Alborosie

The balanced equation for reaction of solid cesium with liquid water

= 2Cs + 2H2O → 2CsOH + H2

cesium react with liquid water to produce cesium hydroxide and hydrogen gas

that is 2 moles of Cs react 2 moles of H2O to form 2 moles CsOH and 1 of hydrogen gas

4 0
3 years ago
Read 2 more answers
In a typical analysis, 15 ml of an aqueous solution containing an unknown amount of acetylcholine had a ph of 7.65. When incubat
melomori [17]

pH of the acetyl choline solution before incubation = 7.65

[H_{3}O^{+}]=10^{-7.65}=2.24*10^{-8}M

pH of the solution after incubation = 6.87

[H_{3}O^{+}]=10^{-6.87}=1.35*10^{-7}M

The difference in concentration of hydronium ion before and after incubation

=1.35*10^{-7}M-2.24*10^{-8}M=1.126*10^{-7}M

This difference in hydronium ion concentration can be attributed to the increase in the concentration of acetic acid, which is formed when acetylcholine is hydrolyzed by acetycholinesterase. The mole ratio of acetylcholine to acetic acid is 1:1.

Therefore the moles of acetylcholine = 15 mL * \frac{1L}{1000mL}*\frac{1.126*10^{-7}mol }{L}=1.689*10^{-9}mol


7 0
2 years ago
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