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Flura [38]
3 years ago
15

What does 1 N = ? please I need help?​

Physics
2 answers:
strojnjashka [21]3 years ago
5 0

1~N = 1~ \text{kg~ms}{^{-2}

7nadin3 [17]3 years ago
4 0

1 N = 1 kg × m/s²

One Newton is equal to 1 kilogram multiplied by meter by second squared.

_____

Hope it helps ⚜

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What kind of friction exists between solid objects moving in water?
eduard
Fluid Friction exists when it is acted upon an object when in fluid.


6 0
3 years ago
A restaurant records the number of tables served each night, and the results have the values: minimum = 3, lower quartile = 14,
dybincka [34]

To choose the correct box plot, verify each of the options and make sure all the values in the plot match the values provided.

<h3>How to identify the median?</h3>

In a box plot, this value is represented by a vertical line located in the middle of the graph.

<h3>How to identify the maximum and the minimum?</h3>

The maximum is the value located on the farthest right, while the minimum is located on the farthest left.

<h3>How to identify the quartiles?</h3>

Divide the graph into 4 and analyze how much each quartile represents.

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5 0
2 years ago
Consider five atoms from the second period : lithium , beryllium , boron , carbon , and nitrogen , which of these elements has t
kap26 [50]

Answer:

Lithium has the lowest electronegativity.

Explanation:

Electronegativity measures the tendency of an atom to attract the bonding pair of electrons. As we move left to right in a period, the number of shell remains same but the number of electron increases(negative charge increases. Hence, electronegativity also increases.

As Lithium is the left most element in this period. It has the lowest electronegativity value which is equal to 0.98.

6 0
3 years ago
suppose 1 gold bar is 6 cm long, 2 cm high, and 3 cm wide. how many whole gold bars will you be able to fit in a vault with a vo
Gemiola [76]
To determine the number of gold bars that would fit in the vault, determine the volume (v) of a single gold bar.
                              v = l x h x w
where l, h, and w are length, height and width, respectively. Substituting the known values, 
                            v = (6 cm)(2 cm)(3 cm) = 36 cm³
The number of gold bars can be determined by dividing the volume of the vault by the volume of the gold bar,
                                      n = (500 cm³ / 36 cm³) = 13.89
Thus, the maximum number of gold bars in the vault is 13.

5 0
3 years ago
A 1420-kg car is traveling with a speed of 12.4 m/s. What is the magnitude of the horizontal net force that is required to bring
zzz [600]

Answer:

1419.01436 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-12.4^2}{2\times 78}\\\Rightarrow a=-0.98564\ m/s^2

The force on the car

F=ma\\\Rightarrow F=1420\times -0.98564\\\Rightarrow F=-1419.01436\ N

Magnitude of the horizontal net force that is required to bring the car to a halt is 1419.01436 N

3 0
3 years ago
Read 2 more answers
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