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zubka84 [21]
3 years ago
14

I need answers please i will give you 20

Physics
2 answers:
iren2701 [21]3 years ago
5 0
Yes it will, amplitude has influence on speed.
chubhunter [2.5K]3 years ago
5 0
The answer is Yes! It will be louder but if you decrease the amplitude it will be softer
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Antireflection coatings can be used on the inner surfaces of eyeglasses to reduce the reflection of stray light into the eye, th
Basile [38]

Answer:

1.33

Explanation:

Using the formula for destructive interference since the two reflected ray light waves from eyeglass should be made to cancel each other ( destructive interference) and also refractive index of air less than the refractive index of the film and both are less than the refractive index of the glass meaning the both reflected rays from the air and film will experience a phase change

n film =  ( m + 0.5) ( λ / 2t)

since 2 t = ( m + 0.5) ( λ / n film)

where m is an integer, λ is wavelength, and t is thickness  and n film is the refractive index of film

for effectiveness m = 0

n film = ( 0.5) ( 480 ÷ (2 × 90 ) ) = 1.33

4 0
4 years ago
Bro i need help omg.
sergey [27]

Answer:

25.

Explanation:

8 0
3 years ago
Read 2 more answers
A child should ride in a place in the vehicle where an adult can always be watching.
almond37 [142]

Answer:

True. mark me as Brilliant

3 0
3 years ago
A planet is 15 light years from earth. At which of the following speeds will the crew of a spaceship complete the trip to the pl
Svetradugi [14.3K]

Answer:

option c) 0.88c is the correct answer

Explanation:

using the Lorrentz equation we have

t=\frac{d}{v}\sqrt{1-(\frac{v}{c})^2}

where,

t = time taken to cover the distance

d = Distance

v = velocity

c = speed of light

given

d = 15 light years

Now,

8years=\frac{15years\times c}{v}\sqrt{1-(\frac{v}{c})^2}

or

(\frac{v}{c})^2\times (\frac{8}{15})^2=1-(\frac{v}{c})^2

or

(\frac{v}{c})^2\times 0.284=1-(\frac{v}{c})^2

or

(\frac{v}{c})^2\times 0.284 + (\frac{v}{c})^2 =1

or

(1.284\times \frac{v}{c})^2 =1

or

(\frac{v}{c}) =\sqrt{\frac{1}{0.284}}

or

v=0.88c

7 0
3 years ago
UPVOTES FOR EVERY ANSWER!!!!!!!!
mario62 [17]
<span>C. Field lines begin near the magnet’s north pole and extend toward its south pole. 

Hope this helps!</span>
4 0
4 years ago
Read 2 more answers
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