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3 years ago

The fundamental resolution of a lens or telescope is determined by:

Physics

1 answer:

Sliva [168]3 years ago

4 0

Answer:

The numerical aperture of the lens.

Explanation:

A numerical aperture is a dimensionless number that is the range of angles that the system can accept / emit light.

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a force 2.4E2 N exists between a positive charge of 8E-5 C and a positive charge of 3E-5 C. What distance separates the charges?

Verdich [7]

The distance between the two charges is $0.3 m$

Explanation:

The electrostatic force between two charged objects is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the charges of the two objects

r is the separation between the two charges

In this problem, we are given the following:

$q_1 = 8\cdot 10^{-5} C$

$q_2 = 3\cdot 10^{-5} C$

$F=2.4\cdot 10^2 N$

Therefore, we can rearrange the equation to solve for r, the distance between the two charges:

$r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(8.99\cdot 10^9)(8\cdot 10^{-5})(3\cdot 10^{-5})}{2.4\cdot 10^2}}=0.3 m$

Learn more about electrostatic force:

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3 years ago

A Michelson interferometer uses red light with a wavelength of 656.45 nm from a hydrogen discharge lamp. Part A How many bright-

kati45 [8]

Answer:

51793 bright-dark-bright fringe shifts are observed when the mirror M2 moves through 1.7cm

Explanation:

The number of maxima appearing when the mirror M moves through distance \Delta L is given as follows,

$\Delta m = \frac{\Delta L}{\frac{\lambda}{2}}$

Here,

$\Delta L$ = is the distance moved by the mirror M

$\lambda$ is the wavelenght of the light used.

$\Delta L$ = 0.017m

$\lambda = 656.45*10^{-9}m$

$\Delta m = \frac{0.017}{\frac{656.45*10^{-9}}{2}}$

$\Delta m = 51793.72$

Therefore, 51793 bright-dark-bright fringe shifts are observed when the mirror M2 moves through 1.7

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3 years ago

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MA_775_DIABLO [31]

Answer:

Given that refractive index of the material is √2. i.e. n = √2. Hence, critical angle for the material is 45°

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julsineya [31]

The answer is c. velocity

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