Answer:
The angle of twist can be computed using the material’s shear modulus if and only if the shear stress is still in the elastic region
Explanation:
The shear modulus (G) is the ratio of shear stress to shear strain. Like the modulus of elasticity, the shear modulus is governed by Hooke’s Law: the relationship between shear stress and shear strain is proportional up to the proportional limit of the material. The angle of twist can be computed using the material’s shear modulus if and only if the shear stress is still in the elastic region.
Answer:
The length of tank is found to be 0.6 m or 600 mm
Explanation:
In order to determine the length, we need to find a volume for the tank.
For this purpose, we use ideal gas equation:
PV = nRT
n = no. of moles = m/M
Therefore,
PV = (m/M)(RT)
V = (mRT)/(MP)
where,
V = volume of air = volume of container
m = mass of air = 4.64 kg
R = General Gas Constant = 8.314 J/mol.k
T = temperature of air = 10°C + 273 = 283 K
M = molecular mass of air = 0.02897 kg/mol
P = Pressure of Air = 20 MPa = 20 x 10^6 N/m²
V = (4.64 kg)(8.314 J/mol.k)(283 k)/(0.02897 kg/mol)(20 x 10^6 N/m²)
V = 0.01884 m³
Now, the volume of cylindrical tank is given as:
V = 0.01884 m³ = π(Diameter/2)²(Length)
Length = (0.01884 m³)(4)/π(0.2 m)²
<u>Length = 0.6 m = 600 mm</u>
Answer:
See explanation
Explanation:
Solution:-
- The shell and tube heat exchanger are designated by the order of tube and shell passes.
- A single tube pass: The fluid enters from inlet, exchange of heat, the fluid exits.
- A multiple tube pass: The fluid enters from inlet, exchange of heat, U bend of the fluid, exchange of heat, .... ( nth order of pass ), and then exits.
- By increasing the number of passes we have increased the "retention time" of a specific volume of tube fluid; hence, providing sufficient time for the fluid to exchange heat with the shell fluid.
- By making more U-turns we are allowing greater length for the fluid flow to develop with " constriction and turns " into turbulence. This turbulence usually at the final passes allows mixing of fluid and increases the heat transfer coefficient by:
U ∝ v^( 0.8 ) .... ( turbulence )
- The higher the velocity of the fluids the greater the heat transfer coefficient. The increase in the heat transfer coefficient will allow less heat energy carried by either of the fluids to be wasted ; hence, reduced losses.
Thereby, increases the thermal efficiency of the heat exchanger ( higher NTU units ).
Answer:
P > 142.5 N (→)
the motion sliding
Explanation:
Given
W = 959 N
μs = 0.3
If we apply
∑ Fy = 0 (+↑)
Ay + By = W
If Ay = By
2*By = W
By = W / 2
By = 950 N / 2
By = 475 N (↑)
Then we can get F (the force of friction) as follows
F = μs*N = μs*By
F = 0.3*475 N
F = 142.5 N (←)
we can apply
P - F > 0
P > 142.5 N (→)
the motion sliding
Answer:
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