3 years ago

Hunter wants to measure the weight of a dumbbell. He should

Physics

2 answers:

MissTica3 years ago

4 0

Use a scale and record the weight in cm^3

Georgia [21]3 years ago

4 0

Answer:

use a scale and record the weight in N.

Explanatiuse a scale and record the weight in N.on:

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Answer:

Acceleration (a)=change in velocity/ change in time

Velocity (v)=90m/s

Time=0.0005s

a=90/0.0005

The acceleration =180000m/s^2 or 180km/s^2

Force = mass x acceleration

m=40g= 0.04kg

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Explanation:

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A 0.5 m diameter wagon wheel consists of a thin rim having a mass of 7 kg and six spokes, each with a mass of 1.2 kg. 1.2 kg 7 k

Arte-miy333 [17]

Explanation:

It is given that,

Mass of the rim of wheel, m₁ = 7 kg

Mass of one spoke, m₂ = 1.2 kg

Diameter of the wagon, d = 0.5 m

Radius of the wagon, r = 0.25 m

Let I is the the moment of inertia of the wagon wheel for rotation about its axis.

We know that the moment of inertia of the ring is given by :

$I_1=m_1r^2$

$I_1=7\times (0.25)^2=0.437\ kgm^2$

The moment of inertia of the rod about one end is given by :

$I_2=\dfrac{m_2l^2}{3}$

l = r

$I_2=\dfrac{m_2r^2}{3}$

$I_2=\dfrac{1.2\times (0.25)^2}{3}=0.025\ kgm^2$

For 6 spokes, $I_2=0.025\times 6=0.15\ kgm^2$

So, the net moment of inertia of the wagon is :

$I=I_1+I_2$

$I=0.437+0.15=0.587\ kgm^2$

So, the moment of inertia of the wagon wheel for rotation about its axis is $0.587\ kgm^2$ . Hence, this is the required solution.

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A. Divergent (pretty sure)

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