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4 years ago

Which factors are most likely to limit population growth in cloud forests?

Chemistry

1 answer:

antoniya [11.8K]4 years ago

5 0

Answer:

Option (4)

Explanation:

The cloud forests are located at high elevated areas in the tropical and subtropical regions. They are characterized by the presence of clouds that maintains a relatively cold environment, favoring the existence of various type of plant and animal species. The temperature is comparatively low, rich in moisture content and the amount of sunlight also is low in this region. The change in these factors can cause a decrease in the population growth in these cloud forests.

Thus, low moisture content in the atmosphere and excessive amount of sunlight in this type of forest can lead to the reduction in its population.

Hence, the correct answer is option (4).

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Consider the equation: 2NO2(g) N2O4(g). Using ONLY the information given by the equation which of the following changes would in

Reika [66]

I believe the correct answer is the first option. To increase the molar concentration of the product N2O4, you should increase the pressure of the system. You cannot determine the effect of changing the temperature since we cannot tell whether it is an endothermic or an exothermic reaction. Also, decreasing the number of NO2 would not increase the product rather it would shift the equilibrium to the left forming more reactants. The only parameter we can change would be the pressure. And, since NO2 takes up more space than the product increasing the pressure would allow the reactant to collide more forming the product.

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3 years ago

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What is the half life of an isotope that is 75% decayed after 16 days?

inna [77]

Answer:

half life will be 8days

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3 years ago

When a solution containing 1.4000 g of Ba(NO3)2 and 2.4000 g of HSO3NH2 is boiled, a precipitate forms. One possible identity fo

Georgia [21]

Answer:

See explanation for detailed solution

Explanation:

The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3

Number of moles of Ba(NO3)2 = 1.4 g/ 261.337 g/mol = 5.36 × 10^-3 moles

From the reaction equation;

1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2

5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2

For HSO3NH2

Number of moles = 2.4g/97.10 g/mol =0.0247 moles

2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2

0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles

Hence, Ba(NO3)2 is the limiting reactant

The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g

Number of moles = mass/ molar mass

Molar mass = mass/ number of moles

Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g

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4 years ago

Any solid that forms in a liquid during a chemical reaction is called a

Nimfa-mama [501]

it is called precipitant

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4 years ago

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How would you prepare 3.5 L of a 0.9M solution of KCl?

Fudgin [204]

Calculate the mass of the solute in the solution :

Molar mass KCl = 74.55 g/mol

m = Molarity * molar mass * volume

m = 0.9 * 74.55 * 3.5

m = 234.8325 g

To prepare 0.9 M KCl solution, weigh 234.8325 g of salt in an analytical balance, dissolve in a beaker, shortly after transfer with the help of a funnel of transfer to a volumetric flask of 100 cm³ and complete with water up to the mark, then cover the balloon and finally shake the solution to mix

hope this helps!

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4 years ago