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notka56 [123]
2 years ago
9

An 1810-kg truck traveling eastward at 64.4 km/h

Physics
1 answer:
egoroff_w [7]2 years ago
5 0
Hi is together and immediately after the collision are
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What causes air to move recirculate from one place to another
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Answer:air flow and the movement from where it’s coming from

Explanation:

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A football is thrown vertically with an initial velocity of 33m/s. Calculate the velocity of the ball when it’s height increased
tatyana61 [14]

The final velocity becomes 31.48 m/s

<u>Explanation:</u>

Given:

Initial velocity, u = 33 m/s

Height, h = 5m

Final velocity, v = ?

According to Newton's law:

v² - u² = 2gh

where,

g is the acceleration due to gravity and

g = 9.8 m/s²

On substituting the values we get:

v^2 - (33)^2 = 2 X -9.8 X 5\\\\v^2 - 1089 = -98\\\\v^2 = 991\\\\v = 31.48 m/s

Therefore, the final velocity becomes 31.48 m/s

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3 years ago
To calculate the change in kinetic energy, you must know the force as a function of _______. The work done by the force causes t
QveST [7]

Answer:

(c) position

Explanation:

From the work-energy theorem, the workdone by a force on a body causes a change in kinetic energy of the body.

But, remember that the work done (W) by a force (F) on a body is the product of the force and the distance d, moved by the body caused by the force. i.e

W = F x d

This distance is a measure of the position of the body at a given instance.

Therefore, the work done is given by the force as a function of distance (or position).

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3 years ago
Which type radiation can be observed well from Earth's surface?
umka2103 [35]

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4 0
3 years ago
Read 2 more answers
An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb inclined slopes of 35°. What is the minimum coef
navik [9.2K]

An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb inclined slopes of 35°. The minimum coefficient of static friction needed for this claim to be possible is 0.7

In an inclined plane, the coefficient of static friction is the angle at which an object slide over another.  

As the angle rises, the gravitational force component surpasses the static friction force, as such, the object begins to slide.

Using the Newton second law;

\sum F_x = \sum F_y = 0

\mathbf{mg sin \theta -f_s= N-mgcos \theta = 0 }

  • So; On the L.H.S

\mathbf{mg sin \theta =f_s}

\mathbf{mg sin \theta =\mu_s N}

  • On the R.H.S

N = mg cos θ

Equating both force component together, we have:

\mathbf{mg sin \theta =\mu_s \ mg \ cos \theta}

\mathbf{sin \theta =\mu_s \ \ cos \theta}

\mathbf{\mu_s = \dfrac{sin \theta }{ cos \theta}}

From trigonometry rule:

\mathbf{tan \theta= \dfrac{sin \theta }{ cos \theta}}

∴

\mathbf{\mu_s =\tan \theta}}

\mathbf{\mu_s =\tan 35^0}}

\mathbf{\mu_s = 0.700}}

Therefore, we can conclude that the minimum coefficient of static friction needed for this claim to be possible is 0.7

Learn more about static friction here:

brainly.com/question/24882156?referrer=searchResults

8 0
3 years ago
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