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svp [43]
2 years ago
12

1.) A neutron in a reactor makes an elastic

Physics
1 answer:
alisha [4.7K]2 years ago
7 0

Answer:

whats the question?

Explanation:

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What is the average speed of an object travels 60 meters in 3 seconds?
Solnce55 [7]

Answer:

20 metres per second

Explanation:

60/3

7 0
3 years ago
Supongamos que a su mamá se le rompió sus espejuelos para leer. El punto de acercamiento (near point) del ojo de su mamá se encu
blagie [28]
Here’s the link for the answer
7 0
3 years ago
Darren drives to school in rush hour traffic and averages 28 mph. He returns home in mid-afternoon when there is less traffic an
Gala2k [10]

Answer:

distance between school and home is 21 miles

Explanation:

given data

in rush hour speed  s1 = 28 mph

less traffic speed s2 = 42 mph

time t = 1 hr 15 min = 1.25 hr

to find out

distance  d

solution

we consider here distance home to school is d and t1 time to reach at school

we get here distance equation when we go home to school that is

distance = 28 × t1    .......................1

and when we go school to home distance will be

distance = 42 × ( t - t1 )

distance = 42 × ( 1.25 - t1 )     ...................2

so from equation 1 and 2

28 × t1 = 42 × ( 1.25 - t1 )

t1 = 0.75

so

from equation 1

distance = 28 × t1

distance = 28 × 0.75

distance = 21 miles

4 0
3 years ago
Brainiest for Right Person!
stepan [7]

C)Weight

A)An attraction between two objects that have mass

B)Force decreases as distance increases.

grav force of massive planet increases your weight

4 0
4 years ago
When a particle of charge q moves with a velocity v⃗ in a magnetic field B⃗ , the particle is acted upon by a force F⃗ exerted b
melomori [17]

Answer:

3.8\cdot 10^{-16}N

Explanation:

For a charged particle moving perpendicularly to a magnetic field, the magnitude of the force exerted on the particle is:

F=qvB

where

q is the magnitude of the charge of the particle

v is the velocity of the particle

B is the magnetic field strength

In this problem, we have

q=e=1.6\cdot 10^{-19} is the charge of the electron

v=6.0\cdot 10^6 m/s is the velocity

B=4.0\cdot 10^{-4}T is the magnetic field

Substituting into the formula, we find the force:

F=(1.6\cdot 10^{-19} C)(6.0\cdot 10^6 m/s)(4.0\cdot 10^{-4}T)=3.8\cdot 10^{-16}N

8 0
4 years ago
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