Answer:
A standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other specified particles.
All the data is given in the question and these are as follows:-
Moles - 0.75
Na - 6.022*10^{23
The formula we are using to find the molecules is as follows:-
n = \frac{molecule}{Na}n=
Na
molecule
After, putting the value and solving it. we will get
0.75 * 6.022*10^2^3 = 4.5165*10^{23
Answer:
sheesh um noooooohsndndndnc
<u>Answer:</u> The solubility of nitrogen gas at 5.00 atm is
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:
Or,
where,
are the initial concentration and partial pressure of nitrogen gas
are the final concentration and partial pressure of nitrogen gas
We are given:
Putting values in above equation, we get:
Hence, the solubility of nitrogen gas at 5.00 atm is
Answer:
<h2>Density = 0.00026 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
<h3>
</h3>
From the question
mass of air = 1.2 g
volume = 4,555 mL
Substitute the values into the above formula and solve for the density
That's
<h3>
</h3>
= 0.0002634
We have the final answer as
<h3>Density = 0.00026 g/mL</h3>
Hope this helps you
A. Adding iodine
hope this helps