Question

A bacterial population has an exponential growth rate of 11.2% per hour. If there were 480 bacteria initially, what would the bacterial population be after 5 hours

Answer 1

The number of bacterial population after 5 hours is; 816

• The formula for the exponential growth of the population is;

N(t) = N_o(1 + r)^(t)

Where;

N(t) is number of bacteria after t hours

N_o is number of bacteria initially

r is growth rate

t is time

• We are given;

N_o = 480

r = 11.2% = 0.112

t = 5

• Thus;

N(5) = 480(1 + 0.112)^(5)

N(5) = 816.14

• Approximating to a whole number gives; N(5) = 816 bacteria

Read more about exponential growth at; brainly.com/question/15316908