Answer : The concentration of and at equilibrium is, 0.0031 M and 0.0741 M respectively.
Explanation : Given,
Moles of = 0.166 mol
Volume of solution = 2.15 L
First we have to calculate the concentration of
Now we have to calculate the concentration of and at equilibrium.
Initial conc. 0.0772 0 0
At eqm. 0.0772-x x x
The expression for equilibrium constant is:
By solving the term, we get the value of 'x'.
x = 0.0741
Thus,
The concentration of at equilibrium = (0.0772-x) = (0.0772-0.0741) = 0.0031 M
The concentration of at equilibrium = x = 0.0741 M
Answer:
Sr or Strontium
Explanation:
sr: strontium has atomic radius of 255pm
cu: copper has an atomic radius of 128pm
they teach you in chem how to do it based off the chart but I don't remember that method
Molecular mass of HCl :
H = 1.00794
Cl= 35.453
HCl :
1.00794 + 35.453 = 36.46094 g/mol
hope this helps!
Answer : The concentration of B at equilibrium is 0.0262 M.
Solution :
The given equilibrium reaction is,
Initially conc. 3.60 0
At eqm. (3.60-x) 3x
The expression of will be,
Now put all the value in this equation, we get:
By solving the term, we get:
x = 0.00872 M
Thus, the concentration of B at equilibrium = 3x = 3(0.00872 M) = 0.0262 M
Therefore, the concentration of B at equilibrium is 0.0262 M.