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2 years ago

4. You have learned about the common characteristics of inner planets and outer planets. Explain

Chemistry

2 answers:

Delicious77 [7]2 years ago

7 0

Answer:

Sorry but I do not the answer to help you but I will advise you to look in internet for better answer and secondly I think your cheating while doing paper

Ede4ka [16]2 years ago

4 0

Answer:

We all know that the characteristics are proven, not just an opinion, because they meet the correct standards. The four inner planets are formed of rock and metal and have shorter orbits, slower rotation, and no rings. The four outer planets have longer orbits and spins, as well as a composition of gases and liquids, as well as a large number of moons and rings. The outer planets are known as gas giants because they are comprised of hydrogen and helium.

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How many moles of carbon are in 7.87*10^7 carbon atoms

bonufazy [111]

There is 7 moles in C

6 0

3 years ago

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For which of the following reactions does Kc = Kp?

Julli [10]

None of the choices are right

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3 years ago

As an athlete exercises, sweat is produced and evaporated to help maintain a proper body temperature. On average, an athlete los

dmitriy555 [2]

Answer: For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

Explanation:

We are given:

Heat of vaporization for water = 2257 J/g

Amount of sweat lost = 307 grams

Applying unitary method:

For 1 g of sweat lost, the energy required is 2257 Joules

So, for 307 grams of sweat lost, the energy required will be = $\frac{2257J}{1g}\times 307g=692,899J$

Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

7 0

3 years ago

wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.

Papessa [141]

Answer: The value of equilibrium constant for the net reaction is 11.37

Explanation:

The given chemical equations follows:

Equation 1: $A+2B\xrightarrow[]{K_1} 2C$

Equation 2: $2C\xrightarrow[]{K_2} D$

The net equation follows:

$D\xrightarrow[]{K} A+2B$

As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K=K_1\times \frac{1}{K_2}$

We are given:

$K_1=2.57$

$K_2=0.226$

Putting values in above equation, we get:

$K=2.57\times \frac{1}{0.226}=11.37$

Hence, the value of equilibrium constant for the net reaction is 11.37

6 0

3 years ago

What mass of natural gas (CH4) must you burn to emit 264 kJ of heat?

mariarad [96]

The heat released by cpmolete the combustion of organic products with oxygen is called heat of combustion.

Here 1 mol of CH4 realesed 802.3 KJ

To emit 264 kJ you multiply you need (1 mol of CH4/802.3 kJ)* 264 kJ = 0.329 mol of CH4

The molar mass, MM, of CH4 is 12 g/mol + 4*1g/mol = 16 g/mol

The to obtain the mass multiply the number of moles times the molar mass:

mass = n * MM = 0.329mol * 16g/mol = 5.26 grams

Answer: 5.26 grams

7 0

3 years ago