Answer:
True
Explanation:
Theories are ideas which are used to make predictions
The whole Activity , poem and paragraph is missing in the question.
Answer:
(1) Liquid A
(2) Solid A
Explanation:
Using this part of the given poem
Substances and mixtures behave differently,
During boiling and melting most especially
Boiling point of substance is fixed while mixture is not
Substance melts completely but mixture does not
The boiling point of the Pure substance remain fixed after reaching its boiling point this is shown by Liquid A
Solid A is melting completely so Solid A is a pure substance.
Answer: 0.83mol/m3
Explanation:
Number of mole = 2.5 mmol = 0.0025mol
Recall
1L = 0.001m3
Therefore 3L = 3x0.001 = 0.003m3
0.003m3 contains 0.0025mol
Therefore, 1m3 will contain = 0.0025/0.003 = 0.83mol
The concentration in mol/m3 is 0.83mol/m3
Endothermic- endothermal, heat absorbing
Ectothermic- exothermal exoergic energy releasing, heat releasing
Answer: 596 atm
Explanation:
Given that,
Original pressure of balloon P1 = 3atm
Original temperature of balloon T1 = 298K
New pressure of balloon P2 = 6atm
New temperature of balloon T2 = ?
Since pressure and temperature are given while volume is constant, apply the formula for Pressure law
P1/T1 = P2/T2
3 atm / 298K = 6 atm / T2
To get the value of T2, cross multiply
3 atm x T2 = 6 atm x 298K
3 atmT2 = 1788 atmK
Divide both sides by 3 atm
3 atmT2 / 3 atm = 1788 atmK / 3 atm
T2 = 596 atm
Thus, a temperature of 596 atmospheres is required to increase the pressure to 6 atm.
