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3 years ago

PLZ LOOK AT ALL THE QUESTIONS. IF YOU GET THEM ALL, YOU ARE A GOD!!

Chemistry

1 answer:

Brut [27]3 years ago

7 0

B cause it tells how it moves

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1. Name the compound present in a sample of dry air.

aev [14]

Answer:

not air

Explanation:

I think so

hahaha

7 0

2 years ago

A flask with a volume of 3.16 l contains 9.33 grams of an unknown gas at 32.0°c and 1.00 atm. What is the molar mass of the gas?

Inessa05 [86]

Answer:

73.88 g/mol

Explanation:

For this question we have to keep in mind that the unknown substance is a gas, therefore we can use the ideal gas law:

$PV=nRT$

In this case we will have:

P= 1 atm

V= 3.16 L

T = 32 ªC = 305.15 ºK

R= 0.082 $\frac{atm*L}{mol*K}$

n= ?

So, we can solve for "n" (moles):

$1~atm*3.16~L~=~n*0.082~\frac{atm*L}{mol*K}*305.15~K$

$n=\frac{1~atm*3.16~L~}{0.082~\frac{atm*L}{mol*K}*305.15~K}$

$n=0.126~mol$

Now, we have to remember that the molar mass value has "g/mol" units. We already have the grams (9.33 g), so we have to divide by the moles:

$molar~mass=\frac{9.33~grams}{0.126~mol}$

$molar~mass=73.88\frac{grams}{mol}$

7 0

3 years ago

Help plz:)))I’ll mark u Brainliest

Triss [41]

Answer:

Explanation:

We want the energy required for the transition:

CO 2 ( s ) + Δ → C O 2 ( g )

Explanation:

We assume that the temperature of the gas and the solid are EQUAL.

And thus we simply have to work out the product:

2 × 10^ 3 ⋅ g × 196.3 ⋅ J ⋅ g − 1 to get an answer in Joules as required.

What would be the energy change for the reverse transition:

C O 2 ( g ) + → C O 2 ( s ) ?

6 0

3 years ago

What is the maximum amount of kcl that can dissolve in 200 g of water? (the solubility of kcl is 34 g/100 g h2o at 20°c.) (1 poi

Solnce55 [7]

The answer is 68g
hope this helps!!

5 0

3 years ago

8.) If 396 g of Carbon Dioxide (CO2) are produced, what mass of Oxygen

KengaRu [80]

Answer:

480 g of oxygen.

Explanation:

C3H8 + 5O2 ---> 3CO2 + 4H2O

Using the molar masses:

3*12 + 6*16 g of CO2 were formed from 10*16 g O2

132g g CO2 from 160 g O2

1g CO2 from (160/132) g O2

396 g from (160/132) * 396

= 480 g of oxygen.

3 0

3 years ago