Balancing chemical equations<br> (8 questions)

Given the two half-reactions, what must be done in the next step before the reaction can be balanced? Au3+ --> Au I- --> I

Artyom0805 [142]

Answer:

The balance equation is

$2Au^{+3} + 6I^{-}$ → $2Au + 3I_{2}$

Explanation:

first, we have to make sure that the atoms are balanced

$Au^{+3}$ → $Au^{}$

$2I^{-}$ → $I_{2}$

then we proceed to balance charges of each half-reaction

$Au^{+3} + 3e^{-}$ → $Au^{}$

$2I^{-}$ → $I_{2}$ $+ 2e^{-}$

Now we multiply the half-reactions to match the number of electrons in each one

( $Au^{+3} + 3e^{-}$ → $Au^{}$ )x2

( $2I^{-}$ → $I_{2}$ $+ 2e^{-}$ )x3

and now we do the sum of the half-reactions

2 $Au^{+3} + 6e^{-}$ → 2 $Au^{}$

$6I^{-}$ → 3 $I_{2}$ $+ 6e^{-}$

$2Au^{+3} + 6I^{-}$ → $2Au + 3I_{2}$

note: the only atom that needed to be balanced was I

3 0

4 years ago

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If 44.7 g of KCI (MM = 74.55 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the

navik [9.2K]

1.199 M is the concentration of KCI in the resulting solution.

<h3 /><h3>What are moles?</h3>

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

No.of moles of KCI

$Moles = \frac{mass}{molar \;mass}$

$Moles = \frac{44.7 g}{74.5513 g/mol}$

= 0.599 moles

Vol.of the solution,V= 500 ml

= 0.5 liter

Molarity

$Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}$

$Molality = \frac{0.599 moles}{0.5 liter}$

= 1.199 M

Hence, 1.199 M is the concentration of KCI in the resulting solution.

Learn more about moles here:

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6 0

2 years ago

The periodic table organizes elements according to INCREASING

jeyben [28]

C would be the correct answer

5 0

3 years ago

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Calculate the mass of 1.23×1024 helium atoms.

just olya [345]

6.023*1023 He atoms=1 mole He

1.23×1024 helium atoms=1.23×1024/6.023*1023 =2.042 mole He

one mole He=4.0 gm

2.042 mole He=2.042*4.0=8.168 gm

answer in grams of Helium is 8.168 gm

7 0

4 years ago

the element cesium forms a with the charge fill in the blank 2 . the symbol for this ion is , and the name is fill in the blank

yulyashka [42]

The element cesium forms a positive ion with the charge +1 . The symbol for this ion is Ce⁺, and the name is cesium ion. The number of electrons in this ion is 54.

<h3>What group does the element cesium belong to in the periodic table?</h3>

Cesium belong to the Group 1A of the periodic table.

Group 1A elements are known as alkali metals.

The alkali metals react with water to form alkalis. They form ions with a positive charge of +1 by the loss of an electron.

In conclusion, cesium is an alkali metals it belongs to group 1A of the periodic table. It forms a positive ion with a charge of +1 by the loss of an electron.

Learn more about alkali metals at: brainly.com/question/25317545

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6 0

2 years ago

Balancing chemical equations (8 questions)