Answer:
mass of O₂ = 800 g
Explanation:
Formula of Octane = C₈H₁₈
Formula of Oxygen = O₂
Balanced Chemical Reaction:
Octane react with oxygen and produce water and carbon dioxide.
2C₈H₁₈ + 25O₂ ---------> 16CO₂+ 18H₂O
Moles calculation:
From the number of moles of the reactant used in a chemical reaction specific number of product produced. we can find the amount of any reactant and product from the mole ratio of a chemical reaction.
Mole formula =
no. of moles = mass in grams / molecular mass ............... (1)
Given Data:
Molecular Weight of O₂ = (16 x2 ) = 32 g/mol
Mass of O₂ = To be find
Calculations:
2C₈H₁₈ + 25O₂ ---------> 16CO₂ + 18H₂O
2mole 25 mole 16 mole 18 mole
From the above balanced chemical equation it is know that 2 mole of octane consume 25 mole of oxygen.
so we have to calculate the mass of oxygen that is consumed
by using mole formula (1) we can fine the mass of oxygen
we know
Molecular Weight of O₂ = 32 g/mol
number of moles of Oxygen molecule = 25 mol
putting the value in the below formula
no. of moles of O₂ = mass of O₂ / molecular mass of O₂
25 mole = mass of O₂ / 32 g/mol ....... (2)
By rearragming the equation (2)
mass of O₂ = 25 mole x 32 g/mol
mass of O₂ = 25 mole x 32 g/mol
mass of O₂ = 800 g
So in the octan reaction with oxygen 800g of oxygen will use.
