Question

A cube of iron (Cp = 0. 450 J/g•°C) with a mass of 55. 8 g is heated from 25. 0°C to 49. 0°C. How much heat is required for this process? Round your answer to three significant figures. J.

Answer 1

The heat required by the cube of iron has been 602.64 J.

The specific heat has been given as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The heat required has been expressed as:

$\rm Heat=mass\;\times\;specific\;heat\;\times\;\Delta \textit T$

Computation for the heat required by Iron sample

The mass of the sample has been given as 55.8 g

The specific heat of tin has been, $c_p=0.450\;\rm J/g^\circ C$

The change in temperature, ($\Delta T$) has been:

$\Delta T=\text{Final temperature-Initial temperature}\\\Delta T=49^\circ \text C-25^\circ \text C\\\Delta T=24^\circ \text C$

Substituting the values for the heat required:

$\rm Heat=55.8\;g\;\times\;0.450\;J/g^\circ C\;\times\;24^\circ C\\Heat=602.64\;J$

The heat required by the cube of iron has been 602.64 J.

Learn more about specific heat, here:

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