the average single and double n-o bond lengths are 136 pm and 122 pm, respectively. assuming these two structures were to make e
1 answer:
Resonance structures show that chemical species have equal bond lengths and bond angles when in resonance. The bond lengths of the N - O bond in HNO2 is 126pm.
Linus Pauling introduced the idea of resonance to explain the nature of bonding in compounds and ions where a single Lewis structure can not satisfactorily account for the observed properties of the chemical species.
If the two structures are resonance structures, they will have equal N - O bond lengths and bond angles. The bond length will be intermediate between that of a pure N - O single and N - O double bond. The actual N- O bond lengths in HNO2 are obtained as; 136 pm - 122 pm/2 = 126 pm.
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Answer:
There are 12 nanoseconds in .
Explanation:
We need to convert to nanoseconds.
We know that,
Now using unitary method to solve it such that,
So, there are 12 nanoseconds in .
<u>Answer:</u> The new water level of the cylinder is 24.16 mL
<u>Explanation:</u>
To calculate the volume of water displaced by silver, we use the equation:
Density of silver = 10.49 g/mL
Mass of silver = 35.2 g
Putting values in above equation, we get:
We are given:
Volume of graduated cylinder = 20.8 mL
New water level of the cylinder = Volume of graduated cylinder + Volume of water displaced by silver
New water level of the cylinder = (20.8 + 3.36) mL = 24.16 mL
Hence, the new water level of the cylinder is 24.16 mL