What is the ideal temperature for a lithium-ion battery?.
1 answer:
You might be interested in
Answer:
The variation rate is 5.42 10⁻⁵ cm²/ºC
Explanation:
When we have a thermal expansion problem we must have the relationship of the change in length as a function of the temperature, which are given in this problem, so we can write the expression for the area of a rectangle
a = L W
They ask us to find the rate of variation of this area depending on the temperature, so we can derive this expression with respect to the temperature
da / dT = d(LW) / dt
We use the derivative of a product since the two magnitudes change
da / dT = W dL/dT + L dW/dT
The values they give us are
= 1.9 10⁻⁵ cm/ºC
= 8.5 10⁻⁶ cm/ºC
W = 1.6 cm
L= 2.8 cm
Substituting the values and calculating
= 1.6 1.9 10⁻⁵ + 2.8 8.5 10⁻⁶
= 3.04 10⁻⁵ + 2.38 10⁻⁵
= 5.42 10⁻⁵ cm²/ºC
The variation rate is 5.42 10⁻⁵ cm²/ºC
The wavelength of the emitted photon is()= 690nm
To calculate the wavelength of the photon we are using the formula,
Or,
We are given here,
= The energy difference between the two levels = 1. 8 ev=
C.
h= Planck constant = Js.
c= speed of light = m/s.
We have to find the wavelength of the emitted photon = m.
Therefore, we substitute the known parameters in the above equation, we can find that,
Or,
Or, m
Or,=690 nm.
From the above calculation we can conclude that the wavelength of the emitted photon is 690nm.
Learn more about ruby laser:
#SPJ4