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taurus [48]
3 years ago
11

Select the volume units that are greater than one liter.

Physics
2 answers:
Brut [27]3 years ago
4 0
The base units of length and volume are linked in the metric system. By definition, a liter is equal to the volume of a cube exactly 10 cm<span> tall, 10 </span>cm<span> long, and 10 </span>cm <span>wide. Because the volume of this cube is 1000 cubic centimeters and a liter contains 1000 milliliters, 1 </span>milliliter<span> is equivalent to 1 cubic </span>centimeter<span>.</span>
Marat540 [252]3 years ago
3 0
Dekaliter is 10 times bigger than 1 liter.     
1 Dekalite = 10 Liters 
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Vlada [557]

Answer:

Explanation:

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3 years ago
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A 2.0-kg mass is oscillating about the origin at 24 rad/s. The amplitude of the oscillations is 0.040 m. At what position is the
Darya [45]

Answer:

0.0327 m

Explanation:

m = 2 kg

ω = 24 rad/s

A = 0.040 m

Let at position y, the potential energy is twice the kinetic energy.

The potential energy is given by

U = 1/2 m x ω² x y²

The kinetic energy is given by

K = 1/2 m x ω² x (A² - y²)

Equate both the energies as according to the question

1/2 m x ω² x y² = 2 x 1/2 m x ω² x (A² - y²)

y² = 2 A² - 2 y²

3y² = 2A²

y² = 2/3 A²

y = 0.82 A = 0.82 x 0.040 = 0.0327 m

4 0
3 years ago
Weight is the direct result of :<br><br> A. Distance <br><br> B. The amount of gravity being pulled
zheka24 [161]
B i think ........................
4 0
3 years ago
The voltage across a membrane forming a cell wall is 72.7 mV and the membrane is 9.22 nm thick. What is the magnitude of the ele
Blizzard [7]

Answer:

The  magnitude of the  electric field intensity is  E =  7.89  *10^{6} \ V/m

Explanation:

From the question we are told that

    The  voltage is  \epsilon     =  72.7 \ mV  =  72.7 *10^{-3}  V

    The  thickness of the membrane is  t =  9.22 \ nm  =  9.22 *10^{-9} \ m

     

Generally the electric field intensity is mathematically represented as

                E =  \frac{\epsilon }{t}

 substituting values

                E =  \frac{72.7 *10^{-3} }{9.22 *10^{-9}}

                E =  7.89  *10^{6} \ V/m

8 0
3 years ago
A 3.2-kg thin, circular hoop with a radius of 5.4 m is rotating about an axis through its center and perpendicular to its plane.
elena-14-01-66 [18.8K]

Answer:

Torque = –207.4 Nm

Explanation:

Given M = 3.2kg, r = 5.4m, α = –12rad/s² (it is slowing down)

Torque = I × α

α = angular acceleration

I = moment of inertia

I = MR² for a circular hoop

Torque = 3.2×5.4×(– 12)

Torque = –207.4 Nm

6 0
3 years ago
Read 2 more answers
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