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Archy [21]
3 years ago
15

An atom has 2 protons in its nucleus. Which of the following must be true for this atom to have no net electrical charge?

Chemistry
2 answers:
kobusy [5.1K]3 years ago
4 0

Answer:

The atom has 2 negatively charged electrons outside the nucleus.

Explanation:

done the topic it is correct

sp2606 [1]3 years ago
3 0
The 2 correct options I guess are A and D
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8. What is the molecular formula of a compound if 0.50 moles of it contains 0.50
11Alexandr11 [23.1K]

Answer:

ew

Explanation:

de

3 0
3 years ago
A ball was massed in a dish. The total mass was 15.6 grams. Treball was placed in a
iVinArrow [24]

Answer:

14.57g

Explanation:

Given parameters:

Mass of dish + ball  = 15.6g

Initial volume of water in the cylinder  = 26.7mL  

Final volume of water in the cylinder  = 38.9mL

Mass of dish = ?

Unknown

Mass of the ball = ?

Solution;

 Since the mass of ball and dish is 15.6g,

 Mass of the ball  =Mass of ball + dish  - mass of the dish

 Insert the parameters and solve;

 Mass of the ball  = 15.6g  - 1.03g  = 14.57g

3 0
2 years ago
How many liters of oxygen gas, at standard
Karo-lina-s [1.5K]

Answer:

Explanation:

  • For the balanced reaction:

<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)​.</em>

It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.

  • Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:

no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.

  • Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:

<em><u>Using cross multiplication:</u></em>

4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.

0.64 mol of Fe is needed to react with → ??? mol of O₂.

∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.

  • Finally, we can get the volume of oxygen using the information:

<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1 mol of O₂ occupies → 22.4 L, at STP conditions.

0.48 mol of O₂ occupies → ??? L.

∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.

5 0
3 years ago
Science Question 1: Please Answer!
charle [14.2K]
Ok but you have to give me a cookie
7 0
2 years ago
g A radioactive isotope of mercury, 197Hg, decays to gold, 197Au, with a disintegration constant of 0.0108hrs.-1. What % of the
weqwewe [10]

Answer:

7.49% of Mercury

Explanation:

Let N₀ represent the original amount.

Let N represent the amount after 10 days.

From the question given above, the following data were obtained:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Next, we shall convert 10 days to hours. This can be obtained as follow:

1 day = 24 h

Therefore,

10 days = 10 day × 24 h / 1 day

10 days = 240 h

Thus, 10 days is equivalent to 240 h.

Finally, we shall determine the percentage of Mercury remaining as follow:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Log (N₀/N) = kt /2.303

Log (N₀/N) = 0.0108 × 240 /2.303

Log (N₀/N) = 2.592 / 2.303

Log (N₀/N) = 1.1255

Take the anti log of 1.1255

N₀/N = anti log 1.1255

N₀/N = 13.3506

Invert the above expression

N/N₀ = 1/13.3506

N/N₀ = 0.0749

Multiply by 100 to express in percent.

N/N₀ = 0.0749 × 100

N/N₀ = 7.49%

Thus, 7.49% of Mercury will be remaining after 10 days

5 0
2 years ago
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