The force of friction needed to overcome to move the box is 29.4N
According to Newton's second law;
Taking the sum of force along the plane;
This shows that the moving force is equal to the frictional force
Given that
Get the frictional force;
Since
Hence the force of friction needed to overcome to move the box is 29.4N
Learn more here: brainly.com/question/189856
At t = 0 a truck starts from rest at x = 0 and speeds up in the positive x-direction on..., the time the truck passes the car and the coordinate the truck passes the car is mathematically given as
<h3>What time does the truck pass the car and coordinate does the truck pass the car?</h3>
Generally, the equation for Distance traveled is mathematically given as
By Truck
By Car
In conclusion, when the conditions the truck passes the car
Therefore
Therefore
differentiation of T
Read more about Speed
brainly.com/question/4931057
#SPJ1
K.E.=mv^2/2=>
m=0.15
v=35m/s
0.15•35^2/2
183.75/2=91.87
The component of weight(
mg) that is responsible for the motion of boxes on ramp is:
Where m = mass of the boxes.
g = Acceleration due to gravity = 9.8
= The angle the ramp makes with the ground. In this case it is 30°.
Since the frictional force is:
μ*N.
Where,
μ = Frictional Coefficient
N = Normal to the ramp =
Therefore, the frictional force becomes =
= μ*
Apply Newton's second law we would get:
- μ*
=
=>
=
μ
-- (A)
Now according to equation of motion:
Where x = 5.8m
= 0
= 0
= 10.24
Plug in the value in the above equation you would get:
= 1.1328
Plug in
in equation (A) and solve for
μ, you would get,
μ = 0.4439
Answer:
Explanation:
Given,
mass of the bullet, m = 0.0233 Kg
Mass of the block, M = 2.41 Kg
horizontal spring constant, k = 845 N/m
Amplitude of oscillation, A = 0.196 m
Using conservation of energy when the bullet is embedded
PE = KE
Now using conservation of momentum to calculate the initial velocity of bullet