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2 years ago

1. Three students are using sports equipment to model the relative motion of

Physics

2 answers:

Alex Ar [27]2 years ago

3 0

The basketball would be sun then baseball earth and finally golf ball moon.

djyliett [7]2 years ago

3 0

Answer:

The golf ball would be revolving around the baseball while the baseball would be revolving around the basketball.

Explanation:

The basketball would be represented as the Sun, the baseball would be represented as the Earth and the golf ball would be represented as the moon. Since the Moon revolves around the Earth and the Earth revolving around the Sun makes a perfect explaination for this question.

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An ambulance with a siren emitting a whine at 1800 hz overtakes and passes a cyclist pedaling a bike at 2.23 m/s. after being pa

Anna71 [15]

It's the Doppler Effect that "up and down sound."

I was on Yahoo--- Brainly doesn't have an option for Credientials or Site credit, so I'll just put this in the quotes:

The formula for doppler effect is always (s is speed and f is frequency): 
f_perceived.by.observer = f_of.emitted.wave * (s_wave + s_observer) / (s_wave + s_source.of.wave) 

And you should pay attention to the signs: 
s_observer is positive if the receiver is moving towards the source, negative otherwise 
s_source.of.wave is positive if the source is moving away from the observer, negative otherwise 

Applying it to this case: 

s_source.of.wave = ? (positive), speed of ambulance 
s_observer = + 2.44 m/s speed cyclist 
f_of.emitted.wave =1800 Hz frequency of whine 
f_perceived.by.observer = 1760 frequency heard by cyclist 
s_wave = 343 m/s speed of sound in air 

Now you know every value in the equation for doppler effect except by s_source.of.wave, so you can solve for s_source.of.wave.

5 0

3 years ago

Please need help on this thank you

lys-0071 [83]

I am pretty sure it is B....

6 0

3 years ago

"what is the period of one vibration of this tone?"

Viktor [21]

The full question is:
On a keyboard, you strike middle C, whose frequency is 256 Hz. What is the period of one vibration of this tone?
The period of a vibration is the time it takes for the particle to make one full oscillation. Frequency is by definition number of full oscillations per unit of time.
When the frequency is expressed in Hz that unit of time is one second.
So there is the following relation between frequency and period:
$T=\frac{1}{f}$
When we plug in the numbers we get:
$T=\frac{1}{256}=0.0039$s$

7 0

3 years ago

A 4-kg object is moving with a speed of 5 m/s at a height of 2 m. The kinetic

tatyana61 [14]

Hello!

$\large\boxed{KE = 50J}$

Use the formula for kinetic energy:

$KE = \frac{1}{2}mv^{2}$

Plug in the given mass and velocity:

$KE = \frac{1}{2} (4)5^{2}$

Simplify:

$KE = \frac{1}{2} (100)\\\\KE = 50 J$

7 0

3 years ago

Saturn moves in an orbit around the Sun with radius 10 AU. How many degrees does it move on the Celestial in one year? (Hint: Ca

Lana71 [14]

Answer:

B. About 12 degrees

Explanation:

The orbital period is calculated using the following expression:

T = 2π*( $\sqrt{\frac{r^3}{Gm}}$ )

Where r is the distance of the planet to the sun, G is the gravitational constant and m is the mass of the sun.

Now, we don't actually need to solve the values of the constants, since we now that the distance from the sun to Saturn is 10 times the distance from the sun to the earth. We now this because 1 AU is the distance from the earth to the sun.

Now, we divide the expression used to calculate the orbital period of Saturn by the expression used to calculate the orbital period of the earth. Notice that the constants will cancel and we will get the rate of orbital periods in terms of the distances to the sun:

$\frac{Tsaturn}{Tearth}$ = $\sqrt{\frac{rSaturn^3}{rEarth^3} } = \sqrt{10^3}}$

Knowing that the orbital period of the earth is 1 year, the orbital period of Saturn will be $\sqrt{10^3}}$ years, or 31.62 years.

We find the amount of degrees it moves in 1 year:

$1year * \frac{360degrees}{31.62years} = 11.38 degrees$

or about 12 degrees.

6 0

3 years ago