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2 years ago

8

1. Three students are using sports equipment to model the relative motion of

2 answers:

Alex Ar [27]2 years ago

3 0

The basketball would be sun then baseball earth and finally golf ball moon.

djyliett [7]2 years ago

3 0

Answer:

The golf ball would be revolving around the baseball while the baseball would be revolving around the basketball.

Explanation:

The basketball would be represented as the Sun, the baseball would be represented as the Earth and the golf ball would be represented as the moon. Since the Moon revolves around the Earth and the Earth revolving around the Sun makes a perfect explaination for this question.

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The acceleration due to gravity on the moon is about 1/6 of the acceleration due to gravity on the earth. A net force F acts hor

uysha [10]

Answer:

c. $a_m$

Explanation:

We are given that

Acceleration due to gravity on the moon= $a_m$

Acceleration due to gravity on the earth= $a_e$

$g_m=\frac{1}{6}g_e$

Net force due to am on an object on moon= $F_{net}=ma_m$

There is no friction and no drag force and there is no gravity involved

Then, the force acting on an object on earth= $F=ma_e$

$F=F_{net}$ (given)

$ma_m=ma_e$

$a_e=a_m$

Hence, option c is true.

3 0

2 years ago

Altitude means the what?

andrew-mc [135]

Answer:

the height of a object or point relation to sea level or ground level

7 0

3 years ago

Is energy matter? Is gravity matter? Why or why not

Alja [10]

No, because the energy is the capacity for performing work. Gravity is the force that draws everything to the earth's center.

5 0

3 years ago

A car moves with a speed of 30 metres per second calculate the distance travelled in 30 seconds

Leni [432]

30x30=900

The answer is 900 meters after 30 seconds

7 0

2 years ago

One hazard of space travel is the debris left by previous missions. There are several thousand objects orbiting Earth that are l

MariettaO [177]

Answer:

F = 6666.7 N

Explanation:

Given that,

Mass of a chip, m = 0.1 mg

Initial speed, u = 0

Final speed, $v=4\times 10^{3}\ m/s$

Time of collision, $t=6\times 10^{-8}\ s$

We know that,

Force, F = ma

Put all the values,

$F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.1\times 10^{-6}\times (4\times 10^3-0)}{6\times 10^{-8}}\\\\F=6666.7\ N$

So, the required force is 6666.7 N.

3 0

3 years ago