How many different elements are present in c6h12o6
1 answer:
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Answer:
Explanation:
For this question we have:
-) A solution NaOH 0.25 M
-) 500 g of glyceryl tripalmitoleate (tripalmitolein)
We can start with the <u>reaction</u> between NaOH and tripalmitolein. NaOH is a base and tripalmitolein is a triglyceride, therefore we will have a <u>saponification reaction</u>. The products of this reaction are <u>glycerol and (E)-hexadec-9-enoate</u>.
Now, with the reaction in mind, we can calculate the <u>moles of NaOH</u> that we need if we use the molar ratio between NaOH and tripalmitolein (3:1) and the molar mass of tripalmitolein (801.3 g/mol). So:
With the moles of NaOH we can <u>calculate the volume</u> (in litters) if we use the molarity equation and the Molarity value:
Now we can do the <u>conversion</u> to mL:
I hope it helps!