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Airida [17]
3 years ago
6

Why is electricity considered a secondary source of energy

Engineering
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:

The electricity that we use is a secondary energy source because it is produced by converting primary sources of energy such as coal, natural gas, nuclear energy, solar energy, and wind energy, into electrical power.

Explanation:

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The dc machine of Problem 7.4 is to be operated as a motor supplied by a constant armature terminal voltage of 250 V. If saturat
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Answer: If saturation effects are ignored, the magnetization curve of Fig. 7.27 becomes a straight line with a constant slope of 150 volts per ampere of field current.

Explanation:

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Consider a car manufacturing firm, with more than 100 facilities worldwide. What would be the positive aspects of having high nu
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More work getting done and faster
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Mining is an example of this type of business
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Mining would go under Industry organization.

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4 years ago
Two resistors, with resistances R1 and R2, are connected in series. R1 is normally distributed with mean 65 and standard deviati
Sedbober [7]

Answer:

n this question, we are asked to find the probability that  

R1 is normally distributed with mean 65  and standard deviation 10

R2 is normally distributed with mean 75  and standard deviation 5

Both resistor are connected in series.

We need to find P(R2>R1)

the we can re write as,

P(R2>R1) = P(R2-R1>R1-R1)

P(R2>R1) = P(R2-R1>0)

P(R2>R1) = P(R>0)

Where;

R = R2 - R1

Since both and are independent random variable and normally distributed, we can do the linear combinations of mean and standard deviations.

u = u2-u1

u = 75 - 65 = 10ohm

sd = √sd1² + sd2²

sd = √10²+5²

sd = √100+25 = 11.18ohm

Now we will calculate the z-score, to find  P( R>0 )

Z = ( X -u)/sd

the z score of 0 is

z = 0 - 10/11.18

z= - 0.89

4 0
4 years ago
Technician A says that a 12 Volt light bulb that draws 12 amps has a power output of 1 watt. Technician B says that a motor that
Artemon [7]

Answer:

Technician B

Explanation:

Resistance, R=\frac {V}{I} where V is the voltage and I is the current in amps

Therefore, R=\frac {12}{12}=1 ohm

Power=VI=12*12=144 W

Therefore, the power is 144 W and resistance is 1 Ohm. This implies that technician A is wrong while technician B is correct

6 0
4 years ago
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