Answer:
c. A program that offers discounts to libraries and schools ensuring they have affordable access to modern telecommunications and information services.
Explanation:
Federal E-Rate program refers to the Schools and Libraries Program of the Universal Service Fund managed by the Universal Service Administrative Company (USAC) and being directed by the Federal Communications Commission (FCC).
The program offers telecommunications and internet access to schools and libraries in the United States at discounts of between 20% and 90% in order to make the services affordable to them.
The discounts received by each of he beneficiary schools receive which is between the rage of 20% and 90% is determined by the degree of poverty and the urban/rural status of the population or students being served.
In the program, connectivity and maintenance services are provided by the Schools and Libraries Program, while school that applied to the program has to provide other items like software, hardware (e.g. computers), and among other items that will make then to use the connectivity provided.
I wish you the best.
Answer:
The correct response will be "0.992". The further explanation to the following question is given below.
Explanation:
The probability that paging would be beneficial becomes 0.8
Effective paging at the very first attempted is 0.8
On the second attempt the success probability will be:
⇒ ![0.2\times 0.8](https://tex.z-dn.net/?f=0.2%5Ctimes%200.8)
⇒ ![0.16](https://tex.z-dn.net/?f=0.16)
On the third attempt the success probability will be:
⇒ ![0.2\times 0.2\times 0.8](https://tex.z-dn.net/?f=0.2%5Ctimes%200.2%5Ctimes%200.8)
⇒ ![0.032](https://tex.z-dn.net/?f=0.032)
So that the success probability will be:
⇒ ![0.8 + 0.16 + 0.032](https://tex.z-dn.net/?f=0.8%20%2B%200.16%20%2B%200.032)
⇒ ![0.992](https://tex.z-dn.net/?f=0.992)
Answer: The overhead percentage is 7.7%.
Explanation:
We call overhead, to all those bytes that are delivered to the physical layer, that don't carry real data.
We are told that we have 700 bytes of application data, so all the other bytes are simply overhead, i.e. , 58 bytes composed by the transport layer header, the network layer header, the 14 byte header at the data link layer and the 4 byte trailer at the data link layer.
So, in order to assess the overhead percentage, we divide the overhead bytes between the total quantity of bytes sent to the physical layer, as follows:
OH % = (58 / 758) * 100 = 7.7 %
Answer:
I am in 6th grade why am i in high school things.
Explanation: