Question

Solve and answer the two questions at the bottom

Answer 1

Considering the definition of electrostatic:

a. The strength of the electrostatic force between the ions is 8.224×10⁻¹⁶ N.

b. the force is repulsive.

Electrostatic forces result from the interaction of electric charges with an electromagnetic force. That is, the electromagnetic force is the interaction that occurs between bodies that have an electric charge.

Coulomb's law states the value of an electrostatic force. This force depends on the opposing charges and the distance between them.

So, Coulomb's law states that the force is inversely proportional to the square of the separation between the two particles and is proportional to the product of the charges on the particles:

$F=k\frac{q1q2}{d^{2} }$

where q1 and q2 are the charges of the particles, d their separation and k is a constant known as Coulomb's constant or vacuum electrical constant.

In this case, you know:

• k= 9×10⁹ $\frac{Nm^{2} }{C^{2} }$
• q1= 6.4×10⁻¹⁷ C
• q2= 9.6×10⁻¹⁶ C
• d= 8.2×10⁻⁴ m

Replacing:

$F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{6.4x10^{-17} Cx9.6x10^{-16}C }{(8.2x10^{-4} m)^{2} }$

Solving:

$F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{6.144x10^{-32} C^{2} }{(8.2x10^{-4} m)^{2} }$

$F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{6.144x10^{-32} C^{2} }{6.724x10^{-7} m^{2} }$

$F=9x10^{9} \frac{Nm^{2} }{C^{2} }9.137x10^{-26} \frac{C^{2} }{m^{2} }$

F= 8.224×10⁻¹⁶ N

a. The strength of the electrostatic force between the ions is 8.224×10⁻¹⁶ N.

Electrostatic forces can be:

• of attraction: when the charges are different, and they attract each other.
• of repulsion: when the charges are equal and repel each other.

b. In this case, since the sign of the charges is the same, the force is repulsive.

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