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Vesnalui [34]
2 years ago
9

The motor of an electric drill has a power input of 1200 W. How much work 3 points

Physics
1 answer:
elixir [45]2 years ago
7 0

Answer:

Explanation:

1 Watt = 1 J/s

1200 J/s(2 min)(60 s/min) = 144 KJ

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A 2.5 kg block is launched along the ground by a spring with a spring constant of 56 N/m. The spring is initially compressed 0.7
Norma-Jean [14]

vf ^2 = kx^2/m = 56(0.75)^2 / 2.5 = 12.6


Therefore, v= 3.5 m/s.

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How does Doppler ultrasound technology differ from ultrasound technology
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Answer:

. Doppler ultrasound is based on absorption of sound, and other

ultrasound technology is based on reflection.D.

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Calculate the force at sea level that a boy of mass 50 kg exerts on a chair in which he is sitting.
kogti [31]

As per the question the mass of the boy is 50 kg.

The boy sits on a chair.

We are asked to calculate the force exerted by the boy on the chair at sea level.

The force exerted by boy on the chair while sitting on it is nothing else except the force of gravity of earth i.e the weight of the body .The direction of that force is vertically downward.

At sea level the acceleration due to gravity g = 9.8 m/s^2

Hence the weight of the boy w = mg  [m is the mass of the body]

we have m = 50 kg.

                             Hence w = 50 kg ×9.8 m/s^2

                                             =490 N kg m/s^2

                                              = 490 N

Here newton [N] is the unit of force.





6 0
3 years ago
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A dentist using a dental drill brings it from rest to maximum operating speed of 391,000 rpm in 2.8 s. Assume that the drill acc
krek1111 [17]

Answer:

a

    \alpha  =  2327.7 \ rev/s^2

b

   \theta = 9124.5 \ rev

Explanation:

From the question we are told that

    The maximum  angular   speed is  w_{max} =  391000 \ rpm  =  \frac{2 \pi  *  391000}{60} =  40950.73 \ rad/s

     The  time  taken is  t =  2.8 \ s

     The  minimum angular speed is  w_{min}= 0 \ rad/s this is because it started from rest

     

Apply the first equation of motion to solve for acceleration we have that

       w_{max} =  w_{mini} +   \alpha  *  t

=>     \alpha  = \frac{ w_{max}}{t}

substituting values

       \alpha  = \frac{40950.73}{2.8}

       \alpha  =  14625 .3 \  rad/s^2

converting to rev/s^2

  We have

           \alpha  =  14625 .3 *  0.159155 \ rev/s^2

           \alpha  =  2327.7 \ rev/s^2

According to the first equation of motion the angular displacement is  mathematically represented as

       \theta  =  w_{min} * t  + \frac{1}{2} *  \alpha  *  t^2

substituting values

      \theta  =  0  * 2.8  + 0.5  *  14625.3  *  2.8^2

      \theta  = 57331.2 \  radian

converting to revolutions  

        revolution = 57331.2 *  0.159155

        \theta = 9124.5 \ rev

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Venus should be the correct answer
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3 years ago
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