3 years ago

Find the remainder when the sum of the six smallest primes is divided by the seventh.

Mathematics

2 answers:

Anastasy [175]3 years ago

7 0

Answer:

Step-by-step explanation:

Six smallest prime numbers: 2, 3, 5, 7, 11, 13

Sum: 41

Seventh smallest prime number: 17

41/17 = 2 R7

almond37 [142]3 years ago

3 0

Answer:

Step-by-step explanation:

The first 7 prime numbers are ...

2, 3, 5, 7, 11, 13, 17

The sum of the first 6 is ...

(2 +3 +5 +7 +11 +13) = 41

Dividing this sum by 17 gives ...

41/17 = 2 r 7

The remainder is 7.

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