It's not clear to me what the given interval is supposed to be, so I'll use a generic one, [a, b] with a < b.
The average acceleration of the particle over this interval is given by the average rate of change of v(t),

Answer:
The factors of the polynomial are:
(x + 1) and (x - 3).
Step-by-step explanation:
Answer: It is A
Step-by-step explanation: Just did it on edg2020
Answer:
Area of triangle ABC=7 square units
Area of triangle A'B'C'=7 square units
Step-by-step explanation:
Triangle ABC is the preimage of triangle A'B'C' under a reflection in the line x=0.
The two triangles are congruent so they have the same area.
We can calculate the area by counting the unit squares the triangle covered.
Each full box is 1 units square.
Each triangle covered
1 full box and 12 partially covered boxes.
Each partial box covered is 0.5 square units.
Therefore the area is


square units