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pav-90 [236]
3 years ago
10

We are just a bunch of molecules that hang out together but don't touch each other. Is this believable? If this is the case, wha

t goes on in the body that allows us to "feel" when we touch something? How is this related to an object applying a force to another object?
Physics
1 answer:
inn [45]3 years ago
3 0
While the idea that we are a bunch of molecules that do not ever "touch" may seem counterintuitive, it is indeed the case. If we think about the structure of an atom, it is made of a nucleus composed of protons and neutrons, and surrounded by electrons. The electrons are moving at very high speeds in random directions all around the nucleus creating electromagnetic fields, defined by various wave functions. These electron clouds are essentially what do the "touching" between molecules.

When two molecules come in contact with each other, rather than solid particles physically touching, it is the two electron clouds of each molecule that are interacting and essentially repelling each other. If we try to bring two negatively charged species together, they will naturally repel one another. Therefore, when two electron clouds try to interact, the electrons will electrostatically repel each other. When this occurs, the force that each electron cloud exerts electrostatically on the other cloud is transmitted to their nuclei.This is how it is related to general objects applying forces to one another. The force of repulsion felt by the electron clouds is ultimately transmitted to the nerve cells in our skin which is perceived as pressure and a sense of touch, despite the fact that no particles are physically touching.
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Question 1 (1 point)
MatroZZZ [7]

Answer:

The work done by the frictional force is 600J.

Explanation:

The work W done by the frictional force is

W= Fd.

Now, F = 60N and d =10m; therefore,

W= (60N)(10m)

\boxed{W = 600J.}

Hence, the work done by friction is 660J.

7 0
3 years ago
Given that the distance from the left end of the string to the first antinode is 27.5 cm , calculate the wavelength of the stand
ivolga24 [154]

Answer:

= 0.55 m

Explanation:

A standing wave is characterized by anti-nodes and nodes.

Antinodes are points on a standing wave at maximum amplitude, while nodes are points on the standing wave that are stationary and have zero amplitude.

The distance between two adjacent nodes or two adjacent anti-nodes is equivalent to half the wavelength.

Therefore, in this case the half wavelength is 27.5 cm.

Thus, wavelength = 27.5 × 2

                              = 55 cm

                             <u>= 0.55 m</u>

6 0
3 years ago
The connections of many simple pieces in the brain is evidence of the:
olga55 [171]

Brian’s Complexity Brian’s Complexity Brian’s Complexity Brian’s Complexity

6 0
3 years ago
Read 2 more answers
A circular radar antenna on a coast guard ship has a diameter of 2.10 m and radiates at a frequency of 16.0 ghz. two small boats
solmaris [256]
By definition,
q = 1.22y/D

Where,
q = min. angle
y = wavelength
D = Aperture diameter = diameter of the antenna

At distance "x" from the antenna,
L =xq = 1.22xy/D
Where, L = Min. distance

But, y =c/f = (3*10^8)/(16*10^9) = 0.01875 m

Substituting;
L = 1.22*5*10^3*0.01875/2.1 = 54.46 m
5 0
3 years ago
The cylinder with piston locked in place is immersed in a mixture of ice and water and allowed to come to thermal equilibrium wi
lukranit [14]

Answer:

a. volume of gas:  (decreases)

b. temperature of gas:  (same)

c. internal energy of gas: (same)

d. pressure of gas: (increases)

Explanation:

We have a gas (let's suppose that is ideal) in a piston with a fixed volume V.

Then we put in a reservoir at 0°C (the mixture of water and ice)

remember that the state equation for an ideal gas is:

P*V = n*R*T

and:

U = c*n*R*T

where:

P = pressure

V = volume

n = number of mols

R = constant

c = constant

T = temperature.

Now, we have equilibrium at T = 0°C, then we can assume that T is also a constant.

Then in the equation:

P*V = n*R*T

all the terms in the left side are constants.

P*V = constant

And knowing that:

U = c*n*R*T

then:

n*R*T = U/c

We can replace it in the other equation to get:

P*V = U/c = constant.

Now, the piston is (slowly) moving inwards, then:

a) Volume of the gas: as the piston moves inwards, the volume where the gas can be is smaller, then the volume of the gas decreases.

b) temperature of the gas: we know that the gas is a thermal equilibrium with the mixture (this happens because we are in a slow process) then the temperature of the gas does not change.

c) Internal energy of the gas:

we have:

P*V = n*R*T = constant

and:

P*V = U/c = constant.

Then:

U = c*Constant

This means that the internal energy does not change.

d) Pressure of the gas:

Here we can use the relation:

P*V = constant

then:

P = (constant)/V

Now, if V decreases, the denominator in that equation will be smaller. We know that if we decrease the value of the denominator, the value of the quotient increases.

And the quotient is equal to P.

Then if the volume decreases, we will see that the pressure increases.

4 0
2 years ago
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