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Vikentia [17]
2 years ago
15

Calculate the energy required to produce 183 grams Cl2O7 on the basis of the following balanced equation. [ Cl=35.5 g/mol g, O=1

6 g/mol g],
2Cl2(g) + 7O2(g) + 130 kcal --->2Cl2O7 (g)
Chemistry
1 answer:
erica [24]2 years ago
3 0
2ci2g+702 is wrong so the absolute great vita
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1. Which one is the odd one out?<br> 0 CaO<br> o Cu<br> o CO<br> o CH
Sauron [17]

Answer:

Yttrium barium copper oxide (YBCO) is a family of crystalline chemical compounds, famous for displaying high-temperature superconductivity.It includes the first material ever discovered to become superconducting above the boiling point of liquid nitrogen (77 K) at about 92 K.Many YBCO compounds have the general formula Y Ba 2 Cu 3 O 7−x (also known as Y123),

Explanation:

i hope this makes sense and helps man

4 0
4 years ago
It’s easier to determine the elecron configurations for the p-block elements in periods 1,2,3 than to determine the electrons co
kotegsom [21]
<span>It’s easier to determine the elecron configurations for the p-block elements in periods 1,2,3 than to determine the electrons configurations for the rest of the p-block elements in the periodic table beacause from period 4, specifically from the element 31 (Ga), the atoms start to fill the d orbitals, and the energy levels of the 3d orbitals ara quite similar to the energy levels of 4p orbitals. So, for the elements Cr and Cu the right configurations do not match the configurations predicted using Aufbau method and Hund rules. Those are not the only exceptions but the two first. All is due to the proximity of the energy of the d and p orbitals and the fact that the rearrangement of the electrons result in a lower energy level. </span>
3 0
3 years ago
Read 2 more answers
What mass (in grams) of Mg(NO3)2 is present in 151 mL of a 0.350 M solution of Mg(NO3)2?
Mademuasel [1]

Answer is: A) 7.84 g.

V(Mg(NO₃)₂) = 151 mL ÷ 1000 mL/L.

V(Mg(NO₃)₂) = 0.151 L; volume of the magnesium nitrate.

c(Mg(NO₃)₂) = 0.352 M; molarity of the solution.

n(Mg(NO₃)₂) = V(Mg(NO₃)₂) · c(Mg(NO₃)₂).

n(Mg(NO₃)₂) ) = 0.151 L · 0.352 mol/L.

n(Mg(NO₃)₂) = 0.0531 mol; amount of the substance.

M(Mg(NO₃)₂) = Ar(Mg) + 2Ar(N) + 6Ar(O) · g/mol.

M(Mg(NO₃)₂) = 24.3 + 2·14 + 6·16 · g/mol.

M(Mg(NO₃)₂) = 148.3 g/mol; molar mass.

m(Mg(NO₃)₂) = n(Mg(NO₃)₂) · M(Mg(NO₃)₂).

m(Mg(NO₃)₂) = 0.0531 mol · 148.3 g/mol.

m(Mg(NO₃)₂) = 7.84; mass of magnesium nitrate.

6 0
3 years ago
Read 2 more answers
state two methods that can be used to prepare chlorine from rock salt.write an equation in each case​
Levart [38]

Answer:

electrolysis of brine

Explanation:

Rock salt deposits are usually mined; occasionally water is pumped down, and brine which contain 25 percent of sodium chloride is found

so d brine is electrolyzed to produce chlorine

7 0
2 years ago
The net charge of an ionic compound is
nadya68 [22]

Answer:

D

Explanation:

Any ionic compound will have a net charge of zero.

5 0
3 years ago
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