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Gnom [1K]
4 years ago
8

Define dry cell? Pls tell me ASAP!

Physics
1 answer:
shepuryov [24]4 years ago
6 0

Answer:

a primary cell having a zinc anode, a carbon (graphite) cathode surrounded by manganese dioxide, and a paste containing ammonium chloride as electrolyte.

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The cheetah is one of the fastest-accelerating animals, because it can go from rest to 19.6 m/s (about 44 mi/h) in 2.9 s. If its
Vitek1552 [10]

Answer:

a)P =14288.4 W

b)P = 19.16  horsepower

Explanation:

Given that

m= 108 kg

Initial velocity ,u= 0 m/s

Final velocity ,v= 19.6 m/s

t= 2.9 s

Lets take acceleration of Cheetah is a m/s²

We know that

v= u  + a t

19.6 = 0 + a x 2.9

a= 6.75 m/s²

Now force F

F= m a

F= 108 x 6.75 N

F= 729 N

Now the power P

P = F.v

P = 729 x 19.6 W

P =14288.4 W

We know that

1 W= 0.0013  horsepower

P = 19.16  horsepower

P =14288.4 W

5 0
4 years ago
You have created a circuit in science class. You are using a 9 volt battery. You have generated what type of current?
marishachu [46]

Batteries produce direct current.

5 0
4 years ago
Read 2 more answers
Light passes through the following structures in which order
VladimirAG [237]

Question:The complete question can be found in the attached image below.

Answer: Light passes through the eyes through the following correct order

cornea--> aqueous humor---> lens -------------------->vitreous humor.

Explanation:

The CORNEA is a dome shaped structure that covers the anterior part of the eye. Light rays passes through it first as it enters the eye. The AQUEOUS HUMOR is located anterior to the lens which nourishes the lens and helps to maintain intraocular pressure. Light rays pass through it to the LENS. The lens is a clear structure inside the eye that focuses light rays onto the retina. The light rays passes from lens to the VITREOUS HUMOR before reaching the retina. vitreous humor is a jelly-like substance that fills the center of the eye. I hope this helps, thanks

3 0
3 years ago
Four 50-g point masses are at the corners of a square with 20-cm sides. What is the moment of inertia of this system about an ax
deff fn [24]

Answer:

moment of inertia I ≈ 4.0 x 10⁻³ kg.m²

Explanation:

given

point masses = 50g = 0.050kg

note: m₁=m₂=m₃=m₄=50g = 0.050kg

distance, r, from masses to eachother = 20cm = 0.20m

the distance, d, of each mass point from the centre of the mass, using pythagoras theorem is given by

= (20√2)/ 2 = 10√2 cm =14.12 x 10⁻² m  

moment of inertia is a proportion of the opposition of a body to angular acceleration about a given pivot that is equivalent to the entirety of the products of every component of mass in the body and the square of the component's distance from the center

mathematically,

I = ∑m×d²

remember, a square will have 4 equal points

I = ∑m×d² = 4(m×d²)

I = 4 × 0.050 × (14.12 x 10⁻² m)²

I = 0.20 × 1.96 × 10⁻²

I =  3.92 x 10⁻³ kg.m²

I ≈ 4.0 x 10⁻³ kg.m²

attached is the diagram of the equation

7 0
3 years ago
Magnetic Field: is a region around the charged particle where the electric force is exerted on other charged particles.
nalin [4]
The answer for this question should be TRUE
8 0
2 years ago
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