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Gnom [1K]
3 years ago
8

Define dry cell? Pls tell me ASAP!

Physics
1 answer:
shepuryov [24]3 years ago
6 0

Answer:

a primary cell having a zinc anode, a carbon (graphite) cathode surrounded by manganese dioxide, and a paste containing ammonium chloride as electrolyte.

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Which statement describes a surface wave?
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Answer: A surface wave is a wave that moves along the interface of two different materials, like air and water.

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Which term describes the amount of water vapor in the air?
loris [4]
That would be humidity
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Which would most likely cause molten rock material to become glassy igneous rock?
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The cooling on earth's surface (extrusive)  makes a molten rock to become glassy. The lava cools so fast that crystals don't have time to form, which makes it glassy. Hope this helps!
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3 years ago
What causes air to move recirculate from one place to another
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Answer:air flow and the movement from where it’s coming from

Explanation:

6 0
3 years ago
Un montañero de 65kg de masa ha ascendido a la cima del Everest, la montaña más alta del mundo de 8848m de altura sobre el nivel
andrew-mc [135]

Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (\Delta W), medido en joules, que reducida a:

\Delta W = m\cdot g\cdot \Delta z (1)

Donde:

m - Masa del montañero, medido en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

\Delta z - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que m = 65\,kg, g = 9,807\,\frac{m}{s^{2}} y \Delta z = 500\,m, entonces el trabajo realizado por el montañero para subir es:

\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)

\Delta W = 318727,5\,J

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

7 0
3 years ago
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